Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedaudited 2026-09-22
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Finite-dimensionality requires dominance integrality

Statement

Assume the Axiom of Choice. Every functional λh is the highest weight of a finite-dimensional simple module over the complex semisimple Lie algebra g.

Facts & Assumptions

Given: The Axiom of Choice, g=sl2(C) with Cartan subalgebra h=Ch and simple root α, α(h)=2, with coroot hα (Coroot of a Lie-algebra root, The special linear Lie algebra sl_2), and the functional λh defined by λ(h)=1.

[A1]

The Axiom of Choice is assumed; it enters through the root-space theory used by [L1] (The Axiom of Choice).

[L1]

The highest weight of every finite-dimensional irreducible module is dominant integral, that is, λ,α=λ(hα)Z0 for every simple root (Finite-dimensional highest weights are dominant integral, Integral, dominant, and strictly dominant weights).

[L2]

For sl2 the coroot of the root α satisfies hα=h, since α(h)=2 forces the normalisation hα=2Hα/α(Hα) with Hα dual to α; hence for the functional λ of the Given line, λ,α=λ(h)=1. [definition of the coroot]

[L3]

A finite-dimensional simple highest weight module has a highest weight vector of some weight, and that highest weight is well defined (Highest-weight vectors and modules, Irreducible, completely reducible, and faithful representations).

Refutation

technique · direct
1.1

Suppose a finite-dimensional simple sl2-module V had highest weight λ; then by [L1] the pairing λ,α would be a nonnegative integer.

L1L3A1
2.1

But by [L2] that pairing equals λ(h)=1, which is a negative integer, and in particular is not in Z0; this contradicts step 1.1.

L2step 1.1
3.1

Hence the functional λ with λ(h)=1 is not the highest weight of any finite-dimensional simple module, so the universal statement of the Statement section is false; the failed conclusion is the claim that arbitrary functionals occur as highest weights of finite-dimensional simple modules.

step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

27 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources