Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

FALSE: limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c) whenever both sides exist

Statement

False claim: if ARA \subseteq \mathbb{R}, if f:ARf : A \to \mathbb{R}, if cAc \in A is a limit point of AA (Limit point, isolated point, adherent point, derived set, and dense subset of R\mathbb{R}) and if the limit of ff at cc exists (The ε\varepsilon-δ\delta limit limxcf(x)=L\lim_{x \to c} f(x) = L of f:ARf : A \to \mathbb{R} at a limit point cc of AA), then

limxcf(x)=f(c).\lim_{x \to c} f(x) = f(c) .

Both sides of the asserted equation are defined under the stated hypotheses: the left because the limit is assumed to exist and is single valued (At a limit point of the domain a function has at most one limit), the right because cAc \in A. The claim is that they always agree, and that is false.

Why it is tempting. The condition f(x)L<ε|f(x) - L| < \varepsilon is imposed on points xx arbitrarily close to cc, and it feels as though x=cx = c were the limiting case of that. It is not: The ε\varepsilon-δ\delta limit limxcf(x)=L\lim_{x \to c} f(x) = L of f:ARf : A \to \mathbb{R} at a limit point cc of AA quantifies over 0<xc<δ0 < |x - c| < \delta, and the strict inequality on the left removes x=cx = c from the quantifier entirely. Changing the value of ff at the single point cc therefore changes nothing on the left-hand side and everything on the right.

What is true. The equation above is not a theorem but a condition, and it is the condition the next page of this track takes as the definition of continuity at cc. This library states it as a hypothesis and never as a consequence; hypothesis (i) of Composition of limits holds under either hypothesis: ff is defined at LL with value MM, or gg avoids LL on a punctured neighbourhood of cc is exactly this condition for the outer function.

Facts & Assumptions

Given: The set A:=RA := \mathbb{R}, the point c:=0c := 0, and the function f:RRf : \mathbb{R} \to \mathbb{R} defined by f(x):=0f(x) := 0 for x0x \ne 0 and f(0):=1f(0) := 1.

[L1]

The limit condition: limxch(x)=L\lim_{x \to c} h(x) = L means that for every real ε>0\varepsilon > 0 there is a real δ>0\delta > 0 such that every xx in the domain of hh with 0<xc<δ0 < |x - c| < \delta satisfies h(x)L<ε|h(x) - L| < \varepsilon (The ε\varepsilon-δ\delta limit limxcf(x)=L\lim_{x \to c} f(x) = L of f:ARf : A \to \mathbb{R} at a limit point cc of AA).

[L2]

Limit point: cc is a limit point of SS when every punctured neighbourhood Nε(c)N^{*}_{\varepsilon}(c) meets SS; and punctured neighbourhoods in R\mathbb{R} are never empty (Limit point, isolated point, adherent point, derived set, and dense subset of R\mathbb{R}, The ε\varepsilon-neighbourhood and the punctured ε\varepsilon-neighbourhood of a point of R\mathbb{R}).

[L3]

Absolute value: 0=0|0| = 0, and u0|u| \ge 0 (Basic properties of the absolute value).

[L4]

Order in R\mathbb{R}: trichotomy, so every real either equals 00 or does not, and never both; and 0<10 < 1, so 101 \ne 0 (The multiplicative identity is positive, Ordered field).

Refutation

technique · direct
1.1

The point c=0c = 0 lies in A=RA = \mathbb{R} and is a limit point of R\mathbb{R}: for every real ε>0\varepsilon > 0 the punctured neighbourhood Nε(0)N^{*}_{\varepsilon}(0) is nonempty and is contained in R\mathbb{R}, so it meets R\mathbb{R}.

L2
1.2

ff is a well-defined function on R\mathbb{R}, since by trichotomy every real either equals 00 or does not, exclusively; and the reals 00 and 11 are distinct.

L4
2.1

The limit of ff at 00 exists and equals 00: given an arbitrary real ε>0\varepsilon > 0, take δ:=1>0\delta := 1 > 0; every xRx \in \mathbb{R} with 0<x0<10 < |x - 0| < 1 has x0|x| \ne 0, hence x0x \ne 0, hence f(x)=0f(x) = 0 and f(x)0=0=0<ε|f(x) - 0| = |0| = 0 < \varepsilon.

step 1.1step 1.2L1L3L4
3.1

Yet f(0)=1f(0) = 1, and 10=limx0f(x)1 \ne 0 = \lim_{x \to 0} f(x). So at the point c=0c = 0 of the domain, which is a limit point of the domain, the limit exists and differs from the value: the claim is false.

step 1.2step 2.1L4

Remarks

  • The witness is the smallest possible one. It differs from a constant function at exactly one point, and the limit cannot see that point. Any function agreeing with a constant off cc and taking a different value at cc would serve equally well; the companion page works this witness out in full, computes its one-sided limits, and shows that redefining the single value repairs the equality.

  • Where the false claim does hold. Under the extra hypothesis that limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c) — which is what continuity at cc will mean — it holds trivially, and that is the only sense in which it is ever true. It is emphatically not a consequence of the limit existing.

  • The consequence for composition. Because f(c)f(c) is invisible to the limit, substituting an inner function that takes the value cc is not licensed by the limits alone; that is the content of FALSE: limxcf(g(x))=M\lim_{x \to c} f(g(x)) = M whenever limxcg=L\lim_{x \to c} g = L and limyLf=M\lim_{y \to L} f = M, whose witness is built from this one.

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 33 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources