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A continuous map of compact Hausdorff spaces is an ultrafilter-algebra homomorphism
Statement
Let be continuous between compact Hausdorff spaces, and let be their ultrafilter-limit maps. Then
so is an ultrafilter-algebra homomorphism.
Facts & Assumptions
Given: A continuous map of compact Hausdorff spaces and an ultrafilter on .
The pushforward is an ultrafilter on , and ultrafilter pushforward is functorial (Pushforward sends ultrafilters to ultrafilters and is functorial).
Every ultrafilter on a compact Hausdorff space has exactly one limit (A given ultrafilter on a compact Hausdorff space has a unique limit).
A -algebra homomorphism satisfies (Algebra and algebra homomorphism for a monad).
Proof
Push forward along to the ultrafilter on supplied by [L1].
If converges to , then for each neighbourhood of , continuity makes a neighbourhood of and hence a member of . Therefore , so the pushforward converges to .
Taking , uniqueness in the target gives .
Since , step 3.1 is the equation in [L3]. Thus is an algebra homomorphism, including for the unique map from an empty compact space.
Depends on
- A given ultrafilter on a compact Hausdorff space has a unique limit
- Pushforward sends ultrafilters to ultrafilters and is functorial
- Algebra and algebra homomorphism for a monad
- Continuity of a map of topological spaces at a point and globally
- Convergence and cluster points of a filter on a topological space
Used by
Dependency tree · two levels
16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. Goubault-Larrecq, Algebras of filter-related monads: I. Ultrafilters and Manes' theorem (standard reference, not scraped)