How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Polyline interpolation and equal-length redistribution approximate a smooth arc-length path
Statement
Let , let be an integer, and let be a unit-speed curve with equal arc-length intervals of length . Suppose and the coordinate third derivatives satisfy the bound in Second-order centered and unequal-step tangent estimates with constant . For sufficiently small , each chord length satisfies , where depends only on . The piecewise-linear interpolant through the samples differs from in supremum norm by at most . If this polygon is redistributed by linear interpolation at equally spaced cumulative-length targets, the th redistributed image is within of , for every .
Here on means that is the restriction of a curve on an open interval containing ; derivatives at the endpoints are the continuous one-sided values, and the unit-speed and derivative bounds are required on .
Facts & Assumptions
Given: The unit-speed curve, equal arc-length mesh, derivative bounds, and small-mesh condition in the Statement.
The unit-speed hypothesis [A1] means on . Thus the normalized tangent convention of Regular minimum-energy paths on a declared collision-free tube gives on this interval.
Second-order centered and unequal-step tangent estimates: the coordinate third-derivative bound used here is on the path interval.
The Lagrange and Cauchy forms of Taylor's remainder: its one-dimensional Lagrange formula applies to a scalar function on a closed interval when derivatives through order three are continuous to the endpoints; with degree two it bounds the remainder by , and with degree one it bounds the remainder by .
The chain rule for total derivatives: : differentiating a composition gives the derivative of the outer function applied to the derivative of the inner function.
The curve has the endpoint convention in the Statement, has unit speed on , and has the stated bounds and coordinate third-derivative bound on the whole interval; the interior convention is maps and multi-index derivative notation in Euclidean space.
Given: The data in the Statement.
Proof
On each mesh interval , apply the one-dimensional degree-two formula [F3] to each coordinate of the extended curve at ; the endpoint convention supplies the required derivative continuity, and [A1, F2] gives a remainder vector with . Thus with , , and . Differentiating gives by the chain rule [F4]. Hence for a constant depending only on ; for sufficiently small the chord is at least , so division by its sum with yields .
For with , apply the one-dimensional degree-one formula [F3] on and . The remainder bound in [F3] and give and . Subtracting the linear interpolant cancels the first-order term, so the pointwise interpolation error is bounded by , uniformly over all intervals.
Let and . Step 1.1 gives and . Thus the redistributed target satisfies . Each segment has length at least for small . If target lies on segment at fraction , then ; combining , , and gives .
The point on the true curve at parameter is within of the redistributed polygon point by step 1.2, and it is within of by unit speed and step 2.1. The triangle inequality gives the claimed bound, including endpoints where redistribution fixes the endpoints.
Depends on
- Regular minimum-energy paths on a declared collision-free tube
- $C^k$ maps and multi-index derivative notation in Euclidean space
- Second-order centered and unequal-step tangent estimates
- The chain rule for total derivatives: $D(g\circ f)(a)=Dg(f(a))\circ Df(a)$
- The Lagrange and Cauchy forms of Taylor's remainder
Used by
Dependency tree · two levels
19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Weinan E, Weiqing Ren, and Eric Vanden-Eijnden, String method for the study of rare events (standard reference, not scraped)
- Weinan E, Weiqing Ren, and Eric Vanden-Eijnden, Simplified and improved string method for computing the minimum energy paths in barrier-crossing events (standard reference, not scraped)