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Normal p-subgroups fix block idempotents under Brauer projection

Statement

If DH is a normal p-subgroup of a finite group and k is its splitting residue field, then every central idempotent ekH satisfies BrD(e)=e. In particular every block idempotent of kH belongs to kCH(D).

Facts & Assumptions

Given: The stated normal subgroup and splitting field.

[F1]

Modular block central characters correspond to blocks supplies all central characters and detects the primitive block idempotents.

[F2]

A normal p-subgroup acts trivially on every simple module in characteristic p makes D act trivially on every simple kH-module.

[F3]

The coefficient projection is Brauer homomorphism for a p subgroup.

[F4]

Brauer homomorphism is multiplicative proves its multiplicativity on the fixed algebra.

Proof

1.1

For zZ(kH), normality of D makes CH(D) stable under H, so BrD(z) is central in kH. On a simple module, each D-conjugation orbit outside CH(D) consists of elements with the same action operator by F2. Its coefficients in z are equal, and its length is a positive power of p greater than one. Its sum therefore acts as zero. Removing all these orbits leaves F3's projection. Hence every block character satisfies λb(z)=λb(BrD(z)), by its simple-module construction in F1.

F1F2F3algebra
2.1

If e is central idempotent, its image is a central idempotent by F4 and step 1.1. A central idempotent is the sum of a subset of primitive block idempotents: multiply it by each primitive block and use primitivity to obtain either that block idempotent or zero. F1's characters read exactly the indicator of this subset. Step 1.1 says the two indicators for e and its image agree, so the idempotents themselves agree. This includes e=0,1, D=1, and an empty set of removed orbits. All arguments involve finite sums and require no AC.

F1F4step 1.1algebra

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