Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Variance of a centered random weighted sum

Statement

Let n≥1. Let W1,…,Wn be mutually independent real random variables with finite second moments, means E[Wi]=0, and variances σi2. Let X=(X1,…,Xn) be a real random vector whose coordinates have finite second moments, and suppose the random elements W and X are independent. The coordinates of X need not be mutually independent. For S=∑i=1nWiXi, the variable S is square-integrable, E[S]=0, and Var⁡(S)=∑i=1nσi2E[Xi2].

Facts & Assumptions

Given: Mutually independent centered square-integrable real random variables W1,…,Wn and a square-integrable random vector X=(X1,…,Xn) independent of the vector W=(W1,…,Wn).

[F1]

Independence of random elements means independence of their generated sigma-algebras. (Independent random elements)

[F2]

The joint law of a finite family of independent random elements is the product of their marginal laws. (Independent random elements have product joint law)

[F3]

Measurable coordinatewise maps preserve independence. (Measurable coordinatewise functions preserve independence)

[F4]

Expectations of products of independent integrable random variables factor, and the product is integrable. (Expectations factor over finite products of independent random variables)

[F5]

Sums, products, and lattice operations of measurable real-valued functions used here are measurable. (Arithmetic and lattice operations preserve measurability whenever they are defined)

[F6]

If U,V∈L2(P), then E[∣UV∣]≤(E[U2])1/2(E[V2])1/2. (Cauchy-Schwarz for random variables)

[F7]

Expectation is integration against the probability measure. (Expectation of a nonnegative or integrable random variable)

[F8]

For a square-integrable real random variable Y, Var⁡(Y)=E[(Y−E[Y])2]. (Moments, variance, and covariance on a probability space)

[F9]

Expectation is linear in scalar multiples and binary sums of integrable random variables; repeated use gives the finite-sum rule. (Linearity, monotonicity, and the modulus bound for expectation)

Proof

1.1givenF1F4F6F9

Each Wi and Xi is integrable by [F6] applied with the constant random variable 1. Independence of the two random elements gives independence of Wi and Xi by [F1], so [F4] yields E[WiXi]=E[Wi]E[Xi]=0. Linearity [F9] over the finite index set gives E[S]=0.

1.2givenF2F3F4F5F6

Fix i≠j. The coordinate-product maps (w,x)↦wiwj and (w,x)↦xixj are measurable by [F5]. Since the joint law of (W,X) is the product law by [F2], these maps, one applied to each independent factor, give independent random variables A=WiWj and B=XiXj by [F3]. Both are integrable by [F6]. Also E[A]=E[Wi]E[Wj]=0 by [F4] and mutual independence of the weights. Hence [F4] gives E[WiWjXiXj]=E[AB]=0.

1.3givenF2F3F4

For each i, Wi2 and Xi2 are independent nonnegative random variables by [F2] and [F3]. Applying the nonnegative case of [F4] gives E[Wi2Xi2]=E[Wi2]E[Xi2]=σi2E[Xi2]<∞.

2.1step 1.1step 1.2step 1.3F7F8F9algebra∎

Expanding the finite square S2 gives diagonal terms from step 1.3 and cross terms from step 1.2, so S2 is integrable. Linearity [F9] gives E[S2]=∑iσi2E[Xi2]. By step 1.1, E[S]=0; [F7] and [F8] therefore identify this second moment with Var⁡(S) and prove the claim.

Depends on

Used by

Dependency tree · two levels

42 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources