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Coderivations of the reduced graded symmetric coalgebra are determined by corestrictions

Statement

Let W and Sc(W) be as in Reduced graded symmetric coalgebra with its shuffle coproduct. For any family of degree +1 graded-symmetric maps qn:Sn(W)→W, n≥1, the formula

Q(w1⊙⋯⊙wN)=∑n=1N ∑σ∈Sh⁡(n,N−n)ϵ(σ;w1,…,wN)qn(wσ(1)⊙⋯⊙wσ(n))⊙wσ(n+1)⊙⋯⊙wσ(N)

defines a degree +1 coderivation of Sc(W). It is the unique such coderivation whose projection to S1(W)=W on Sn(W) is qn. For n=N, the final tail is empty and the term means just qN(wσ(1)⊙⋯⊙wσ(N)); in this case Sh⁡(N,0) contains only the identity permutation.

Here a degree-one coderivation is a linear map Q:Sc(W)→Sc(W) that satisfies

ΔˉQ=(Q⊗1+1⊗Q)Δˉ,

where the tensor map 1⊗Q uses the Koszul sign rule. The sum defining Q is finite on each input because n≤N.

Facts & Assumptions

Given: A characteristic-zero graded vector space W, its reduced shuffle coalgebra, and graded-symmetric degree-one maps qn:Sn(W)→W.

[F1]

Reduced graded symmetric coalgebra with its shuffle coproduct: the coproduct is a sum over unshuffles with Koszul signs, and its primitive subspace is W by The graded shuffle coproduct is coassociative, cocommutative, and conilpotent.

[F2]

Koszul sign rule for graded tensor products and permutations: composing graded tensor maps and reordering homogeneous factors multiplies their Koszul signs.

Proof

1.1F1F2construct

The formula is well-defined on the graded-symmetric quotient: replacing a representative by an adjacent graded swap bijects the unshuffle summands, and the Koszul sign in [F2] gives the same graded-symmetric output. Each term is finite because its consumed arity is at most the input length.

1.2F1F2algebra

In ΔˉQ(x), choose the n input labels consumed by one qn, then split the qn output and the unused labels into two nonempty ordered blocks. The same terms occur in (Q⊗1+1⊗Q)Δˉ(x) by first splitting the original labels into those two blocks and applying Q to the block containing the chosen qn inputs. These are the same ordered three-block decompositions; their signs agree by [F2], including the crossing sign from 1⊗Q. Thus the formula satisfies the coderivation identity.

1.3F1induction

Let Q′ be another coderivation with the same corestrictions and put D=Q−Q′. We prove by induction on input length that D=0. On length one, D is its zero corestriction. Assume D=0 on all lengths below N. For x∈SN(W), every tensor factor in Δˉ(x) has length below N; the coderivation identity therefore gives ΔˉD(x)=0. Hence D(x) is primitive.

2.1F1step 1.3discharge-induction∎

By [F1], primitive elements are exactly W, and the length-one projection of D(x) is zero because Q and Q′ have the same corestrictions. Thus D(x)=0. This completes the induction for every finite length, so Q=Q′.

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