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Compatible smooth simplex faces have a neighbourhood extension

Statement

Assume countable choice ACω. Let N be a smooth manifold without boundary. For every codimension-one face Di of D=Δn, let gi:DiN be smooth in the affine-neighbourhood sense. Suppose gi=gj on DiDj. Then there are an open neighbourhood O of D in the affine span E of D and a smooth h:ON with hDi=gi. Only face values are extended, not independently prescribed off-face extensions. No filling of the whole simplex is asserted.

Facts & Assumptions

Given: The compatible face maps and the boundaryless target.

[F1]

Smooth simplex maps have smooth extensions on open affine neighbourhoods (Smooth singular simplex).

[F2]

Under countable choice, the explicit auxiliary construction in the Whitney proof gives a smooth embedding j:NRm, image S, smooth inverse j1:SN, an open US and smooth retraction R:US fixing S (Whitney approximation for manifold-valued maps, Proof 1.1–6.1).

[F3]

The smooth step s is zero on (,0], one on [1,) and takes values in [0,1] (The standard smooth step function).

[A1]

Countable choice is The Axiom of Countable Choice (ACω), the countable instance of The Axiom of Choice; only the former is assumed here.

Proof

1.1

If n=0, take O= and the empty map. Otherwise the face maps glue continuously to g:DN, because the boundary is a finite closed union and the maps agree on all intersections. Fix the data in [F2]. The only infinite-choice use in this proof is the countable embedding construction inherited there.

givenF1F2A1
2.1

At pD write J={i:λi(p)=0} for its incident faces, where λi are barycentric coordinates. Choose one kJ and use the other n coordinates as affine coordinates on E. Shrink around p so every nonincident λi remains positive. For a nonempty IJ, define PI by setting the coordinates in I to zero and adding their sum to λk. Then PIPL=PIL, PIp=p, and PI(D)D by nonnegativity of the retained and added coordinates.

F1step 1.1algebra
3.1

On EI={λi=0:iI} take a smooth Euclidean extension aI of jg on its actual face intersection near p: restrict an extension of jgi for one iI to EI. The intersections of the finitely many inverse extension domains give an open Vp where every aIPI is defined. Set Ap=IJ(1)I+1aIPI. For xVpD, choose j0J with λj0(x)=0. Pair each nonempty I omitting j0 with I{j0}. Their projected points coincide and lie in the actual intersection face, by step 2.1, so compatibility gives equal values with opposite signs. Only I={j0} remains, giving Ap(x)=jg(x). No agreement of the arbitrary extensions outside the actual simplex intersections was assumed.

F1step 1.1step 2.1algebra
4.1

Consider all local data from steps 2.1–3.1 together with balls B(p,r) whose closed doubled balls lie in Vp. They form a cover of compact D. Extract finitely many, indexed by a, with extensions Aa on neighbourhoods of their closed doubled balls. Define ηa(x)=1s((xpa2ra2)/(3ra2)). It equals one on the radius-ra ball and zero outside the radius-2ra ball. The product ηaAa, extended by zero, is globally smooth: its support is contained in a closed ball strictly inside the domain of Aa. This uses a finite subcover of all eligible data, not a simultaneous point-indexed choice.

F3step 2.1step 3.1
5.1

Put w=aηa and O0={w>0}, an open neighbourhood of the boundary. On O0, A=(aηaAa)/w is smooth. At a boundary point every active Aa equals jg, hence A=jg. Thus O=O0A1(U) is open and contains the boundary, and h=j1RA:ON is smooth and restricts to g. This proves the asserted neighbourhood extension.

F2step 3.1step 4.1algebra
6.1

In dimension one the boundary is two points and the same finite construction applies, regardless of their images; a filling is not inferred. Empty target with n>0 cannot satisfy the supplied-face hypothesis. Repeated or constant face values create no exception to the cancellation in step 3.1. The n=0 endpoint was treated in step 1.1; all other selections were finite. The boundaryless hypothesis is essential: compatibility alone does not guarantee nonnegative smooth extensions for a half-space target.

F1A1step 1.1step 3.1step 4.1step 5.1

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