Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Complete-quotient tail formula

Statement

Let α be a real number, let an and αn be its continued-fraction digits and complete quotients, and let pn/qn be the convergents attached to a0,a1,. Whenever αn+1 is defined, α=αn+1pn+pn1αn+1qn+qn1.

Facts & Assumptions

Given: A real number α, its complete quotients αn, and its continued-fraction digits an.

[F1]

The complete quotients satisfy αn=an+1/αn+1 whenever αn+1 is defined. (Complete quotients in the continued-fraction algorithm).

[F2]

For every t>0, [a0;a1,,an,t]=tpn+pn1tqn+qn1. (Convergents are given by the standard recurrences and tail formula).

Proof

technique · direct
1.1

Repeatedly substituting the identities of [F1] yields. [given, F1, algebra] α=[a0;a1,,an,αn+1] whenever αn+1 is defined.

givenF1algebra
2.1

Since every complete quotient after the first is >1, in particular αn+1>0. [step 1.1, F1, F2] So step 1.1 and [F2] give α=αn+1pn+pn1αn+1qn+qn1.

step 1.1F1F2

Depends on

Used by

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources