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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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Continuous functions are dense in Lp of finite tori and of bounded intervals

Statement

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)). Let n≥1 and 1≤p<+∞.

  1. The complex continuous functions on the finite torus Tn are dense in complex Lp(Tn) with respect to the Lp norm (The one-dimensional torus and its normalized Haar integral, Complex Lp classes and Euclidean test-function conventions).
  2. For every bounded interval (a,b)⊆R, the complex continuous functions on [a,b] are dense in complex Lp((a,b)) for Lebesgue measure.
  3. The real versions of 1 and 2 hold, the approximants being the real parts of the complex ones.

Facts & Assumptions

[A1]

Complex Cc∞(Rn) is dense in complex Lp(Rn) for finite p, and complex finite simple functions with finite-measure support are dense in Lp of any measure space (Complex finite-simple and smooth compact-support density for finite p).

[A2]

The torus integral is represented on the fundamental domain [0,1)n, so for G:=[F∘qn]⋅1[0,1)n one has ∥G∥Lp(Rn)=∥F∥Lp(Tn); Minkowski's inequality holds in complex Lp and ∥Re⁡h∥p≤∥h∥p (The one-dimensional torus and its normalized Haar integral, Complex Holder, Minkowski, and the quotient norm).

[A3]

If h∈L1 and ε>0 then some δ>0 has μ(E)<δ⇒∫E∣h∣<ε; the box formula gives λn([0,1)n∖[δ,1−δ]n)=1−(1−2δ)n≤2nδ, and for every real η>0 some δ>0 has 2nδ<η (Absolute continuity of the integral, A box in Rn with parameters ai≤bi is Lebesgue measurable of measure ∏i<n(bi−ai), whichever of its faces are included, For every ε>0 in a complete ordered field there is a natural n≥1 with 1/n<ε).

[A4]

A continuous function t↦dist⁡(t,C) to a closed set is continuous, and maxima and minima of continuous functions are continuous, so the cutoff χ(x):=∏j<nmax⁡{0,1−dist⁡(xj,[δ,1−δ])/δ} is continuous, equals 1 on [δ,1−δ]n and vanishes outside (0,1)n; its support meets only finitely many integer translates of the fundamental cube, so the periodisation K~(s):=∑m∈ZnχH(s+m) is a finite sum locally, is n-fold periodic, and descends to a continuous function K on Tn by the quotient universal property; on [0,1)n the sum reduces to χH (Continuity of a map between metric spaces, at a point and globally, in the ε-δ form, For a quotient map q:X→Y, a map out of Y is continuous iff its composite with q is; a continuous map on X constant on the fibres of q factors uniquely through q; and a composite of quotient maps is a quotient map, The one-dimensional torus and its normalized Haar integral).

[A5]

Proof

technique · direct

Given: Countable Choice, n≥1, 1≤p<+∞, and f∈Lp(Tn;C) represented by the Borel function F.

1.1A2A3

Let G:=F∘qn on [0,1)n, extended by 0 to Rn. Then G∈Lp(Rn) and ∥G∥p=∥f∥Lp(Tn), and for a measurable E⊆Rn with λn(E) small the integral of ∣G∣p over E is small by absolute continuity of the integral.

2.1step 1.1A3

Given ε>0 choose δ>0 with λn([0,1)n∖[δ,1−δ]n)<δ0, where δ0 is a threshold for ∣G∣p and εp from [A3]; put Gδ:=G⋅1[δ,1−δ]n. Then ∥G−Gδ∥pp=∫[0,1)n∖[δ,1−δ]n∣G∣p<εp, so ∥G−Gδ∥p<ε.

3.1step 2.1A1A4

By density of Cc∞(Rn) choose H∈Cc∞(Rn) with ∥Gδ−H∥p<ε, and let χ be the cutoff of [A4] for this δ. Since χ=1 on the support of Gδ and ∣χ∣≤1, one has ∥Gδ−χH∥p=∥χ(Gδ−H)∥p≤∥Gδ−H∥p<ε, and χH is continuous, compactly supported in [0,1]n, and vanishes on the boundary of that cube.

4.1step 2.1step 3.1A2A4

Let K be the continuous function on Tn obtained by periodising χH, as in [A4]; on the fundamental domain K agrees with χH. Therefore, using that the torus Lp integral is represented on [0,1)n and Minkowski's inequality, ∥f−K∥Lp(Tn)=∥G−χH∥Lp([0,1)n)≤∥G−Gδ∥p+∥Gδ−χH∥p<2ε.

5.1step 4.1A1A5

Since ε>0 was arbitrary, claim 1 follows: every f∈Lp(Tn;C) is approximated in Lp by the continuous functions K. For claim 2, let f∈Lp((a,b)) and extend it by 0 to R; the density theorem [A1] gives H∈Cc∞(R) with ∥f−H∥Lp(R)<ε, and restricting H to [a,b] gives a continuous function with ∥f−H∥Lp((a,b))≤∥f−H∥Lp(R)<ε.

6.1step 4.1step 5.1A2

For claim 3, let f be real valued and let H approximate it complexly within ε; then Re⁡H is real continuous and ∥f−Re⁡H∥p=∥Re⁡(f−H)∥p≤∥f−H∥p<ε, so the real continuous functions are dense in each of the two settings.

7.1step 5.1step 6.1∎

Steps 5.1 and 6.1 establish the complex and real density statements on finite tori and on bounded intervals.

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