Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Coordinate-block smoothness descent model

Statement

Let f:Rd→R be continuously differentiable, let Bi be one block of a finite coordinate partition, and let Ui be its coordinate insertion map. Suppose Li>0 satisfies ∥∇if(x+Uih)−∇if(x)∥2≤Li∥h∥2 for every x,h. Then f(x+Uih)≤f(x)+⟨∇if(x),h⟩+Li2∥h∥22.

Facts & Assumptions

Given: The function, block and Lipschitz bound in the Statement.

[F1]

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn, The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case and Laws of finite sums and finite products: identify block label j∈{1,…,d} with standard coordinate j−1 and order each block increasingly; then ∇if(x) is the corresponding restriction of ∇f(x) and ⟨∇f(x),Uih⟩=⟨∇if(x),h⟩ by the finite-coordinate definition of the Euclidean inner product and finite-sum splitting.

[F2]

Continuously differentiable maps, local inverses, and local diffeomorphisms: continuously differentiable means totally differentiable at every point, with continuous derivative entries.

[F3]

The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a): along a differentiable curve, the derivative of the composition is the derivative of the outer function applied to the curve derivative.

[F4]

For a differentiable scalar field, Dvf(a)=⟨∇f(a),v⟩ and the unit direction of steepest ascent is the normalized gradient: for a totally differentiable scalar function, the directional derivative in direction v is ⟨∇f,v⟩.

[F6]

The mean value theorem, as the case g(x)=x of Cauchy's: for f continuous on [a,b] with a<b and differentiable on (a,b) there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a): if a real function is continuous on a closed interval and differentiable in its interior, its endpoint difference is its derivative at an interior point times the interval length.

[F8]

The principle of mathematical induction: an identity that holds at zero and is preserved at successors holds for every natural number.

[F9]

Finite sums and finite products, by recursion and Laws of finite sums and finite products: finite sums satisfy the zero base case, successor recursion, additivity, telescoping, scaling, and the constant-sum law.

[F10]

For every ε>0 in a complete ordered field there is a natural n≥1 with 1/n<ε: for every η>0 there is an integer N≥1 with 1/N<η.

[F11]

Every natural-number-indexed list of nonempty sets has a choice function on its family of values: a finite indexed list of nonempty witness sets has a choice function in ZF.

Proof

1.1givenF1F2F3F4F5F7

If h=0 the claim is equality. Otherwise set ϕ(t)=f(x+tUih) on [0,1]. By [F2] and [F3], ϕ is totally differentiable at every point of [0,1], so [F5] makes it continuous there; [F3] and [F4] give ϕ′(t)=⟨∇if(x+tUih),h⟩. Hence the Lipschitz hypothesis and [F7] give ∣ϕ′(t)−ϕ′(0)∣≤Lit∥h∥22.

2.1F6F8F9F11step 1.1algebra

Fix N≥1 and apply [F6] on each interval [j/N,(j+1)/N]. Each mean-value witness set is nonempty, so [F11] selects cj∈(j/N,(j+1)/N) simultaneously for the finite list j<N, with ϕ((j+1)/N)−ϕ(j/N)=ϕ′(cj)/N. By [F9], summing and telescoping gives ϕ(1)−ϕ(0)−ϕ′(0)=1N∑j<N(ϕ′(cj)−ϕ′(0))≤Li∥h∥22N2∑j<N(j+1). To evaluate the last sum, set TN=∑j<N(j+1); [F9] gives T0=0 and TN+1=TN+(N+1), and [F8] proves TN=N(N+1)/2 by the base case and the algebraic successor identity N(N+1)/2+(N+1)=(N+1)(N+2)/2. Thus the upper bound is Li2(1+1N)∥h∥22.

3.1F10step 2.1assume-contraalgebradischarge-contradiction∎

The left side of step 2.1 is independent of N. If it exceeded Li∥h∥22/2 by δ>0 and Li∥h∥22>0, choose N with 1/N<2δ/(Li∥h∥22) by [F10]; step 2.1 would then give a strict smaller upper bound, a contradiction. If Li∥h∥22=0, step 2.1 already gives the result. Substituting ϕ(1)−ϕ(0)=f(x+Uih)−f(x) and ϕ′(0)=⟨∇if(x),h⟩ proves the inequality.

Depends on

Used by

Dependency tree · two levels

62 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources