Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Strongly convex smooth-part proximal coordinate contraction

Statement

For a finite horizon k, choose an algorithm budget K≥k and do not request a proximal-gradient stopping tolerance, so all k updates are executed.

Let F(x)=f(x)+g(x) on a finite-dimensional block product Rd, where f is convex, continuously differentiable, and globally μ-strongly convex for some μ>0, and g(x)=∑i=1ngi(xBi) with each gi proper, closed and convex. Let B1,…,Bn partition the coordinates into nonempty blocks. Suppose each block gradient is Li-Lipschitz and set Lmax⁡=max⁡iLi. Start from a finite point x0 with F(x0)<+∞. Run Randomized proximal coordinate descent with certified inner solves with uniform independent block sampling and common majorizer Mi=Lmax⁡. For any finite horizon k, assume each of its first k subproblem calls returns an accepted certificate with model error at most ϵj≥0 at update j; exact updates have ϵj=0. Then F has a unique minimizer x∗, μ≤Lmax⁡, and for q=1−μ/(nLmax⁡), E[F(xk)−F(x∗)]≤qk(F(x0)−F(x∗))+∑j=0k−1qk−1−jϵj. The expectation is the finite weighted sum over the k-step block histories, with the power convention q0=1. In particular, exact updates contract the expected gap by the factor q. Curvature of F supplied only by the nonsmooth penalties is not covered.

Facts & Assumptions

Given: The finite block product, f,gi,Li,μ, a finite-valued initial point, uniform independent sampling, and certified model errors from the Statement.

[F1]

Randomized proximal coordinate descent with certified inner solves: the selected block minimizes its quadratic model, or is accepted with certified model gap at most ϵk; other blocks stay fixed.

[F2]

Coordinate proximal subproblems are attained uniquely and descend: every exact block model has a unique minimizer and an accepted error-ϵk update raises F by at most ϵk.

[F3]

Coordinate-block smoothness descent model: the smooth term obeys the block quadratic upper model with constant Li≤Lmax⁡.

[F4]

Finite separable block penalties are proper, closed, and convex: the finite separable sum g is proper, closed and convex; its proof uses only closed sublevels of the block epigraphs and finite products of neighborhoods.

[F5]

A proper closed convex function has an affine minorant: a proper closed convex function on a finite-dimensional Euclidean space has an affine minorant.

[F6]

A finite continuous convex summand preserves proper closed convexity: adding finite continuous convex f to g preserves properness, closedness and convexity.

[F8]

Semicontinuous extreme value theorem on compact Euclidean sets: a real-valued lower-semicontinuous function on a nonempty compact Euclidean set attains its minimum.

[F10]

The principle of mathematical induction: a recurrence bound holding at zero and preserved at successors holds for every finite horizon.

[F11]

Laws of finite sums and finite products: finite weighted sums obey additivity and scaling for averaging over block choices and histories.

[A1]

f(y)≥f(x)+⟨∇f(x),y−x⟩+μ2∥y−x∥22 for all x,y.

[A2]

Mi=Lmax⁡ for every block, Li≤Lmax⁡, and each block is drawn independently and uniformly at every accepted update.

[A3]

Each finite-horizon expectation is the sum over the finite product distribution on block histories.

[A4]

All update calls through the stated horizon return accepted certificates; if an inner call fails, the conclusion is asserted only for the accepted prefix before failure.

Proof

1.1A1F4F5F6F7F8F9givenalgebrachoose

By [F4], g is proper closed convex, so choose xˉ∈dom⁡g. By [F5], g(x)≥⟨a,x⟩+b for some a,b. Strong convexity at 0 yields f(x)≥f(0)+⟨∇f(0),x⟩+μ2∥x∥22, so F is coercive. By [F9], f is continuous, so [F6] gives the closed epigraph of F; the map x↦(x,F(xˉ)) is continuous, so S={x:F(x)≤F(xˉ)} is its closed preimage. Coercivity makes S bounded, and [F7] makes it compact. It is nonempty and finite-valued, so [F8] gives a global minimizer. If two distinct minimizers existed, strong convexity of f at their midpoint and convexity of g would make F there strictly less than the minimum, a contradiction; thus the minimizer is unique.

1.2A1F3givenalgebra

For any block i and nonzero block displacement h, the strong-convexity lower model at x and [F3]'s upper model for x+Uih share the same linear term. Comparing them gives μ∥h∥22/2≤Li∥h∥22/2, so μ≤Li≤Lmax⁡. Therefore α=μ/Lmax⁡ lies in (0,1] and q=1−α/n lies in [0,1).

1.3A2F1F2F3F11givenalgebra

Fix a current finite point x and let zi minimize u↦⟨∇if(x),u−xi⟩+(Lmax⁡/2)∥u−xi∥22+gi(u); [F1]--[F2] give existence. Let z=(zi)i and Hx(w)=f(x)+⟨∇f(x),w−x⟩+(Lmax⁡/2)∥w−x∥22+g(w). This separates over blocks, so z minimizes Hx. For any block candidate v, [F3] and Li≤Lmax⁡ give F(x+Ui(v−xi))≤F(x)+qik(v)−qik(xi). The accepted certificate [F1] gives qik(xik+1)≤qik(zi)+ϵk and qik(xi)=gi(xi), so F(xk+1)≤F(x)+Δi+ϵk, where Δi=qik(zi)−qik(xi). Summing Δi over i gives Hx(z)−F(x). By [F11], uniform averaging yields E[F(xk+1)∣xk=x]≤(1−1/n)F(x)+Hx(z)/n+ϵk.

2.1A1F4step 1.1step 1.2step 1.3algebra

Let x∗ be the minimizer from step 1.1 and w=(1−α)x+αx∗. Convexity of g gives g(w)≤(1−α)g(x)+αg(x∗). Strong convexity in [A1] gives f(x)+α⟨∇f(x),x∗−x⟩≤(1−α)f(x)+αf(x∗)−(αμ/2)∥x−x∗∥22. The quadratic term in Hx(w) is Lmax⁡α2∥x−x∗∥22/2; since α=μ/Lmax⁡, it cancels the negative term. Hence Hx(z)≤Hx(w)≤(1−α)F(x)+αF(x∗).

3.1A3A4F11step 1.3step 2.1algebra

By [A4], substitution of step 2.1 into step 1.3 gives, conditionally on the history, E[F(xk+1)−F(x∗)∣xk]≤q(F(xk)−F(x∗))+ϵk. By [F11] and [A3], taking the finite-history expectation yields ϕk+1≤qϕk+ϵk, where ϕk=E[F(xk)−F(x∗)].

4.1F10step 1.2step 3.1algebra∎

Iterating the scalar recurrence gives ϕ1≤qϕ0+ϵ0; if ϕk≤qkϕ0+∑j<kqk−1−jϵj, then multiplying by q≥0 and adding ϵk proves the formula at k+1. [F10] induction over k establishes the displayed bound.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

78 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources