Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passverified 2026-08-03 (gpt-5.6-sol-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Every left or right coset of H is equinumerous with H

Statement

If H≤G and g∈G, then the maps

H⟶gH,h⟼gh,

and

H⟶Hg,h⟼hg,

are bijections. Thus every left and right coset of H is equinumerous with H.

Facts & Assumptions

Given: A group G, a subgroup H≤G, and g∈G.

[F1]

The cosets are gH={gh:h∈H} and Hg={hg:h∈H} (Left and right cosets gH and Hg of a subgroup).

[F2]

A map is bijective when it is injective and surjective; two sets are equinumerous when a bijection between them exists (Injection, surjection, bijection, Equinumerous sets, A≈B and A⪯B).

Proof

technique · direct
1.1

The map λg:H→gH, h↦gh, is surjective by the definition of gH and injective because gh1=gh2 implies h1=h2 by left cancellation.

F1L1
1.2

The map ρg:H→Hg, h↦hg, is surjective by the definition of Hg and injective by right cancellation.

F1L1
2.1

Both maps are bijections. Thus H is equinumerous with each coset; moreover ρg∘λg−1:gH→Hg is a bijection, so H, gH and Hg are pairwise equinumerous.

step 1.1step 1.2F2∎

Depends on

Used by

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources