Alphabeta Math
DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (z-ai/glm-5.2)verified 2026-07-26 (claude-opus-5)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Equinumerous sets, A≈B and A⪯B

Definition

Let A and B be sets (Injection, surjection, bijection for the terminology).

  • A and B are equinumerous, written A≈B, if there exists a bijection f:A→B.
  • A is dominated by B, written A⪯B, if there exists an injection f:A→B.
  • A≺B abbreviates: A⪯B and not A≈B.

Remarks

  • ≈ behaves like an equivalence relation. It is reflexive (idA is a bijection), symmetric (the inverse of a bijection is a bijection) and transitive (a composition of bijections is a bijection). The careful statement is that these three properties hold for all sets, and that ≈ restricted to any set of sets is an equivalence relation on that set. It is not a relation on "the set of all sets", which does not exist; the reflexivity, symmetry and transitivity statements are schemas about arbitrary sets, which is all any argument below uses.

  • ⪯ is reflexive and transitive, for the same reasons, and A≈B implies both A⪯B and B⪯A. The converse, that A⪯B and B⪯A together give A≈B, is a theorem and not a triviality: it is The Schröder-Bernstein theorem, and it is proved without any use of choice.

  • Subsets. A⊆B implies A⪯B, since the inclusion map is injective. The reverse fails badly for infinite sets: the successor map σ is a bijection N→N∖{0}, being injective and never zero (The von Neumann naturals form a Peano system) and hitting every nonzero natural (Every nonzero natural number is a successor), so N≈N∖{0} and a proper subset can be equinumerous with the whole.

  • ≈ is the library's substitute for "has the same number of elements", stated without introducing cardinal numbers. Everything on this page is phrased with ≈, ⪯ and ≺ alone, so no theory of cardinals is presupposed.

Depends on

Used by

…and 71 more results.

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources