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A countable entourage base can be replaced in ZF by a decreasing symmetric base whose next triple composite lies in the preceding member
Statement
In ZF, every countably based uniformity has a decreasing symmetric base with .
Facts & Assumptions
Given: A countable entourage base .
Symmetric entourages form a base and have square roots (Every uniformity has a base of symmetric entourages).
A nonempty subset of has a least element (The well-ordering principle).
Recursion constructs a sequence from a specified starting value and successor map (The recursion theorem).
Proof
Use the finite listing or bijection supplied by countability to write the given base as , repeating its last member in the finite case. Put Then is a canonically defined decreasing symmetric cofinal base.
Define indices recursively. Put , and let be the least such that ; then put .
Each required set of indices is nonempty: choose a symmetric entourage with , then use cofinality and decreasingness to find with . Thus the recursion is defined. The inequalities give decreasingness and cofinality, while the defining clause gives triple control.
Therefore is the asserted normal base in ZF.
Depends on
Used by
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 33 results over 15 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- J. Wodzicki, Uniform Structure (standard reference, not scraped)
- M. Kunzinger, General Topology (standard reference, not scraped)