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De Giorgi oscillation reduction: one half-level set is small

Statement

Assume Countable Choice and the Axiom of Choice. Let n≥2, let Ω⊆Rn be open, let A and L0 be as in De Giorgi local boundedness of homogeneous subsolutions, and let u∈H1(Ω;R) be a weak solution of L0u=0 on Ω. Write M:=ess sup⁡BR(x0)u, m:=ess inf⁡BR(x0)u and osc⁡BR(x0)u:=M−m for balls BR(x0)⋐Ω. Then the two half-level sets cannot both be large, and one of them is small enough to reduce the oscillation:

  1. (dichotomy) at least one of ∣{u>(M+m)/2}∩BR(x0)∣ and ∣{u<(M+m)/2}∩BR(x0)∣ is at most 12∣BR(x0)∣;
  2. (quantitative reduction) there are constants η=η(n,θ,Ma)∈(0,1) and C=C(n,θ,Ma) such that for every BR(x0) with B2R(x0)⋐Ω, ess osc⁡BR/2(x0)u≤η ess osc⁡BR(x0)u. Moreover the constant η may be chosen as 1−η0/2 where η0>0 depends only on n,θ,Ma; the proof uses localized truncated Caccioppoli estimates and applies the local boundedness estimate De Giorgi local boundedness of homogeneous subsolutions to a nonnegative truncation on the inner ball.

Facts & Assumptions

Given: Countable Choice and the Axiom of Choice; an open Ω⊆Rn, n≥2; a measurable symmetric coefficient field A with θ∣ξ∣2≤⟨Aξ,ξ⟩≤Ma2∣ξ∣2 a.e.; a weak solution u∈H1(Ω;R) of L0u=0; and a ball B2R(x0)⋐Ω.

[F1]

Assume Countable Choice and the Axiom of Choice. Local boundedness: every nonnegative weak subsolution w of L0w=0 on an open set satisfies ess sup⁡Bρr(y)w≤C1(ρ)(1∣Br(y)∣∫Br(y)w2)1/2 for every Br(y)⋐Ω and every 0<ρ<1, with C1(ρ)=C1(n,θ,Ma,ρ) (De Giorgi local boundedness of homogeneous subsolutions).

[F2]

Truncated Caccioppoli estimate and truncation subsolution property. For a solution u of L0u=0 and any k, choose smooth nondecreasing χϵ with χϵ=0 on (−∞,0], χϵ=1 on [ϵ,∞), and χϵ≥0. Testing the local equation with φχϵ(u−k) for nonnegative φ∈Cc∞ is justified by H01 density; expansion gives 0=∫χϵ(u−k)ADu⋅Dφ+∫φχϵ′(u−k)ADu⋅Du, so the first integral is nonpositive. Letting ϵ↓0, the Sobolev chain rule and Du=0 a.e. on {u=k} give a0((u−k)+,φ)≤0. Thus (u−k)+ is a nonnegative local weak subsolution. Also, for Br⋐BR, ∫Br∣D(u−k)+∣2≤C0(R−r)−2∫BR(u−k)+2 with C0=C0(θ,Ma) (Local weak solutions of a divergence-form operator, Weak subsolutions and supersolutions of a divergence-form equation, Positive-part truncation calculus and admissible cut-off weak tests, Caccioppoli inequality for truncated subsolutions, Sobolev level-set step: energy decay with explicit level gap and radius loss).

[F3]

Assume the Axiom of Choice. Smooth functions on the closed ball are dense in H1(BR), and H1(BR) is the closure of C∞(B‾R) under the Sobolev norm; a.e. convergence and L2 convergence of the gradients may be assumed along a subsequence (Ambient smooth restrictions are dense on bounded C^k domains).

[F4]

Measure conventions: ess sup⁡ and ess inf⁡ are the least essential upper and greatest essential lower bounds, and ∣⋅∣ denotes Lebesgue measure. The signed-extrema convention is Weak subsolutions and supersolutions of a divergence-form equation; The essential supremum is attained as the least essential bound and The essential supremum of a measurable function with respect to a measure concern the corresponding absolute essential bound.

[F5]

Fatou's lemma: if nonnegative indicators have pointwise lower limit at least the indicator of a limiting set, then the measure of that set is at most the lower limit of the approximating measures (Fatou's lemma).

Proof

technique · direct; after normalisation the measure of the level sets is driven down by a telescoping De Giorgi iteration, and the local boundedness estimate turns the small measure of the top level set into a sup bound
1.1givenF1F2F4algebra

Dichotomy and normalisation. For any BR(x0)⋐Ω, local boundedness applied to u+ and (−u)+ on slightly larger interior balls gives finite M,m; these truncations are subsolutions by [F2]. The strict sets {u>(M+m)/2}∩BR and {u<(M+m)/2}∩BR are disjoint, so at least one has measure at most ∣BR∣/2, proving claim 1. For claim 2 assume now B2R(x0)⋐Ω. If L:=(M−m)/2=0, then u is constant a.e. on BR and the reduction is immediate. Otherwise define v(y):=(u(x0+Ry)−(M+m)/2)/L on B2(0). It solves the homogeneous equation with rescaled coefficients A(x0+Ry) and the same bounds θ,Ma, with essential extrema 1,−1 on B1. Oscillations scale by L, so it remains to prove ess osc⁡B1/2v≤2−η0 for a universal η0>0. The dichotomy gives the required half-level measure bound on B1.

1.2givenF3F4F5algebra

The measure estimate. Let w∈H1(BR) and t<T. Then ∣{w≤t}∩BR∣ ∣{w≥T}∩BR∣1−1/n≤CnT−t∣BR∣∫BR∣Dw∣dx. For smooth w, fix y with w(y)≥T and write x=y+rω for x with w(x)≤t. Along the segment, T−t≤w(y)−w(x)≤∫0r∣Dw(y+sω)∣ds. Integrating over the low set in polar coordinates, interchanging the radial integrals, and using r≤2R gives ∣{w≤t}∩BR∣≤Cn∣BR∣T−t∫BR∣Dw(z)∣∣z−y∣n−1dz. Integrate this in y over H:={w≥T}∩BR. For every measurable E of finite measure, splitting the kernel integral at radius ∣E∣1/n gives sup⁡z∫E∣z−y∣1−ndy≤Cn∣E∣1/n; hence the asserted inequality follows after division by ∣H∣1/n (the cases ∣H∣=0 or ∣{w≤t}∣=0 are immediate). For general w, choose wj∈C∞(B‾R) converging strongly in H1 and a subsequence converging a.e. Given 0<ϵ<(T−t)/2, apply the smooth inequality to wj at levels t+ϵ,T−ϵ. Pointwise lower limits of the indicators dominate those of {w≤t} and {w≥T}; [F5] passes the left side to the limit, while strong L2 convergence of gradients gives convergence of ∫∣Dwj∣. Letting ϵ↓0 proves the claim. For its transition-set form, apply it to z:=min⁡{(w−t)+,T−t} at levels 0,T−t. Then {z≤0}={w≤t}, {z≥T−t}={w≥T}, and Dz=1{t<w<T}Dw a.e. Thus if ∣{w≤t}∩BR∣≥γ∣BR∣, then Cauchy--Schwarz gives ∣{w≥T}∩BR∣1−1/n≤Cnγ(T−t)∣{t<w<T}∩BR∣1/2(∫BR∣D(w−t)+∣2)1/2. The Sobolev truncation chain rule also gives Dw=0 a.e. on the endpoint level sets.

2.1step 1.2F2algebra

The telescoping iteration. Work with the normalised v of step 1.1 on B1 and suppose first ∣{v>0}∩B1∣≤12∣B1∣. Set s:=(3/4)1/n, so ∣Bs∣=34∣B1∣, and put Tk:=1−2−k−1, Ek:={v>Tk}∩Bs, and Mk:=∣Ek∣. Since {v≤0}∩B1=B1∖({v>0}∩B1) has measure at least 12∣B1∣ and Tk>0, it follows that ∣{v≤Tk}∩Bs∣≥12∣B1∣−∣B1∖Bs∣=14∣B1∣=13∣Bs∣ for every k. The truncated Caccioppoli estimate of [F2], applied with outer radius 1 and inner radius s, gives ∫Bs∣D(v−Tk)+∣2≤C(n,θ,Ma)(1−Tk)2∣B1∣, since v≤1 a.e. on B1. Apply the transition-set inequality of step 1.2 on Bs with t=Tk, T=Tk+1, and γ=1/3. As Tk+1−Tk=(1−Tk)/2, the level gap cancels the Caccioppoli factor and yields Mk+11−1/n≤C(n,θ,Ma)∣B1∣1/2(Mk−Mk+1)1/2,Mk+12−2/n≤C(n,θ,Ma)(Mk−Mk+1). The constant absorbs the fixed volume ∣B1∣.

3.1step 2.1algebra

Summation. Summing the inequalities of step 2.1 over k=0,…,N−1 and using Mk+1≥MN gives NMN2−2/n≤C∑k=0N−1(Mk−Mk+1)=C(M0−MN)≤C∣B1∣, hence MN≤C(n,θ,Ma)N−n/(2n−2)∣B1∣ for every N≥1.

4.1step 3.1F1F2algebra

The top level set is finally small. By [F2], vN:=(v−TN)+ is a nonnegative subsolution of L0w=0. Apply the local boundedness estimate [F1] on outer ball Bs with inner ratio (2s)−1; since B1/2⊂Bs and ∫BsvN2≤MN(1−TN)2, this gives ess sup⁡B1/2vN≤C1(n,θ,Ma)(∣Bs∣−1MN)1/2(1−TN)≤C2N−n/(4n−4)(1−TN) by step 3.1. Choose N=N(n,θ,Ma)≥1 so large that C2N−n/(4n−4)≤12; then v≤TN+12(1−TN)=1−η0 on B1/2 with η0:=12(1−TN)>0.

5.1step 1.1step 4.1algebra∎

Conclusion of the reduction. If instead ∣{v<0}∩B1∣≤12∣B1∣, steps 2.1-4.1 apply verbatim to −v (which is again a solution of the homogeneous equation) and give v≥−1+η0 on B1/2. In the first case ess sup⁡B1/2v≤1−η0 and ess inf⁡B1/2v≥−1, in the second ess sup⁡B1/2v≤1 and ess inf⁡B1/2v≥−1+η0; in both cases ess osc⁡B1/2v≤2−η0. Undoing the affine normalisation of step 1.1 multiplies both oscillations by L and preserves the radius ratio, so ess osc⁡BR/2(x0)u≤(1−η0/2)ess osc⁡BR(x0)u, which is claim 2 with η:=1−η0/2∈(0,1) and with η0, hence η, depending only on n,θ,Ma.

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