Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
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Fatou's lemma

Statement

Let (fn) be nonnegative measurable functions. Then lim infnfndμlim infnfndμ.

Facts & Assumptions

Given: A sequence (fn) of nonnegative measurable functions.

[L1]

Countable infima of measurable extended-real-valued functions are measurable, and monotone pointwise suprema are measurable (Closure properties of measurable functions used by the integral).

[L2]

Monotone convergence holds for the nonnegative integral (Monotone convergence for the integral).

Proof

technique · direct
1.1

For each n, define [L1, given, construct] gn:=infknfk. Then each gn is measurable by [L1], one has gngn+1 and gnlim infnfn pointwise. Also gnfn for every n.

2.1

By [L2], [step 1.1, L2, L3] ∎ lim infnfndμ=limngndμ. Since gnfn, [L3] gives gndμfndμ for every n. Taking the limit in n yields the claimed inequality.

Depends on

Used by

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources