Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Boundary values and log-integrability of Nevanlinna-class functions

Statement

Assume countable choice, as in the defining Nevanlinna and circle conventions. Let f∈N(D) with f≢0. Then f has finite nontangential limits f∗(ζ) for m-almost every ζ∈T, and log⁡∣f∗∣∈L1(T,m); in particular f∗≠0 m-almost everywhere.

Facts & Assumptions

Given: Countable choice and a nonzero f∈N(D).

[F1]

A Nevanlinna function is a quotient f=g/h with bounded holomorphic g,h, h zero-free, and both bounded by one. This construction uses a harmonic conjugate of a majorant and its exponential, without Herglotz representation. (The Nevanlinna class is a bounded quotient class, The Nevanlinna class on the disc)

[F2]

Under countable choice a bounded holomorphic disc function has finite nontangential limits almost everywhere. The same full-measure set works for all cone apertures. (Bounded holomorphic disc functions have Poisson boundary data and Fatou limits under countable choice, The Axiom of Countable Choice (ACω))

[F3]

A nonzero holomorphic function has a finite order at zero, factors there as zmq0 with q0(0)≠0, and has isolated zeros. Holomorphic functions are continuous, and closed bounded annuli in the plane are compact. Jensen's formula on a smaller disc with no boundary zeros gives ∫log⁡∣q0(rζ)∣ dm≥log⁡∣q0(0)∣. Haar measure is normalized to mass one. (The order of a zero is the exponent in its local holomorphic factorization, Identity theorem for holomorphic functions, Zeros of a nonzero holomorphic function are isolated, Heine-Borel in Rn: with the Euclidean metric a subset of Rn is compact if and only if it is closed and bounded, and the proof by bisection uses no choice principle; the same holds on the real line, Complex differentiability at a point implies continuity there, Jensen's formula on a disc, The one-dimensional torus and its normalized Haar integral)

[F4]

For nonnegative measurable functions, the integral of the pointwise limit inferior is at most the limit inferior of the integrals. (Fatou's lemma)

Proof

1.1F1F2givenconstruct

Apply [F1] to write f=g/h with ∣g∣,∣h∣≤1 and h zero-free. Both g and h are nonzero functions, since f≢0. By [F2] they have finite nontangential limits g∗,h∗ almost everywhere. We must prove h∗≠0 and the integrability of both boundary logarithms before dividing.

1.2F2F3F4givenconstructalgebra

Let q be any bounded nonzero holomorphic disc function, with bound M>0. By [F3], its origin order m is finite; the quotient q0=q/zm off zero extends holomorphically to the disc with q0(0)≠0. Its zeros on each closed annulus compactly inside the disc are finite: all open neighborhoods containing at most one zero cover the annulus, by continuity at nonzeros and isolatedness at zeros. Compactness in [F3] gives a finite subcover, bounding the number of zeros by its finite size. For every j≥2, choose rj∈(1−1/j,1−1/(j+1)) whose circle contains no zero; only finitely many radii in this interval are forbidden. Countable choice supplies this sequence. Jensen applied to q0 gives ∫log⁡∣q(rjζ)∣ dm=mlog⁡rj+∫log⁡∣q0(rjζ)∣ dm≥mlog⁡(1/2)+log⁡∣q0(0)∣=:c>−∞. Meanwhile log⁡+∣q(rjζ)∣≤log⁡+M=:C. Consequently ∫log⁡−∣q(rjζ)∣ dm≤C−c. The nontangential limits q∗ of [F2] include radial limits; Fatou [F4] applied to the negative parts, with value +∞ at a zero boundary limit, gives ∫log⁡−∣q∗∣ dm≤C−c<∞. The positive part is bounded by C. Thus log⁡∣q∗∣∈L1 and q∗≠0 almost everywhere. This also covers m=0, a zero-free q and a nonzero constant.

2.1step 1.1step 1.2algebra

Apply step 1.2 separately to g and h. On the common full-measure set where their finite nonzero boundary limits exist, the quotient has finite nontangential limit f∗=g∗/h∗. It is nonzero there, and log⁡∣f∗∣=log⁡∣g∗∣−log⁡∣h∗∣∈L1, by the triangle inequality for the two integrable logarithms. This identifies the complex limit directly, without inferring it from a modulus limit.

3.1step 1.1step 1.2step 2.1algebra∎

Step 2.1 proves the entire assertion. Only countable choice has been used: in the bounded-holomorphic boundary supplier [F2] and the sequence of good Jensen radii in step 1.2. No general positive-harmonic measure representation or full-AC decomposition is needed. The excluded zero function nevertheless has the obvious zero boundary function, a convention used by the class definitions without assigning it an integrable logarithm.

Depends on

Used by

Dependency tree · two levels

125 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources