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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Zeros of a nonzero holomorphic function are isolated

Statement

A holomorphic function on a complex domain that is not identically zero has only isolated zeros.

That is, if f:ΩC is holomorphic on a complex domain and f is not the zero function, then every aΩ with f(a)=0 has a neighbourhood in which a is the only zero of f.

Facts & Assumptions

Given: A complex domain Ω, a holomorphic function f:ΩC that is not identically zero, and an arbitrary zero aΩ.

[L1]

If two holomorphic functions on a complex domain agree on a set with an accumulation point in the domain, then they agree everywhere on the domain (Identity theorem for holomorphic functions).

[L2]

A holomorphic function has finite order m at a exactly when it factors near a as (za)mg(z) with g(a)0; its order is + exactly when it vanishes on a neighbourhood of a (The order of a zero is the exponent in its local holomorphic factorization).

[L3]

A complex differentiable function is continuous at the point of complex differentiability (Complex differentiability at a point implies continuity there).

Proof

technique · direct
1.1

The function f cannot vanish on any neighbourhood of a, for otherwise its zero set would have the interior point a as an accumulation point and [L1], applied to f and the zero function, would make f identically zero on Ω.

L1given
2.1

By step 1.1 and [L2], the order of f at a is finite, so f(z)=(za)mg(z) near a with g(a)0. By [L3], after shrinking the neighbourhood, g is nowhere zero there; since f(a)=0, the finite order m is positive, and a is the only zero of f in that neighbourhood.

step 1.1L2L3
3.1

The zero a was arbitrary, so every zero of f is isolated; if f has no zeros, the conclusion is vacuous.

step 2.1

Depends on

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Dependency tree · two levels

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