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LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Homology of the double branched cover from a Seifert matrix

Statement

Assume the Axiom of Choice. Let K be a smooth oriented knot, let F be a connected compact oriented Seifert surface of genus g, and let V be its positive-push Seifert matrix in any ordered integral basis of H1(F;Z). Then

H1(Σ2(K);Z)≅coker⁡(V+VT).

For g=0, the matrix is empty and the cokernel is trivial.

Facts & Assumptions

Given: Full AC, a smooth oriented knot K, a connected compact oriented Seifert surface F, an ordered integral basis of H1(F;Z), and its positive-push matrix V.

[A1]

Full AC is the choice-function axiom used by the cyclic-cover construction. The Axiom of Choice

[F1]

The double branched cover is Σ2(K) from the connected meridian-mod-2 exterior cover with its lifted meridian filled. Cyclic branched cover of a knot

[F2]

For every q≥2, H1(Σq(K);Z)≅coker⁡(Mq(V)), with diagonal blocks V+VT and adjacent blocks −V and −VT. Seifert block presentation of cyclic branched-cover homology

Proof

1.1givenF2algebra

The block indices in Mq(V) run from 1 to q−1. At q=2 there is only one index, so there are no adjacent blocks and M2(V) consists of the single diagonal block V+VT.

2.1A1F1F2step 1.1given∎

Substitute q=2 in [F2]. By [F1], the resulting manifold is the double branched cover Σ2(K); hence its first homology is the cokernel of V+VT. If g=0, the block has size zero and the cokernel is the zero group by the empty-matrix convention. The required AC hypothesis is inherited through [F1].

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