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Duality eliminates the top and codimension-one handles

Statement

Assume ACω (The Axiom of Countable Choice (ACω)). In the situation of the previous lemma, W also admits a handle decomposition relative to M0 with no handles of index n or n+1; combining the two results, W admits a presentation relative to M0 in which every handle has index between 2 and n−1. Both statements are obtained from the low-index elimination by running it on the reversed triad (W;M1,M0) and dualising (h-Cobordism).

Facts & Assumptions

Given: An h-cobordism (W;M0,M1) with dim⁡W=n+1, n≥5, closed simply connected faces and connected W; ACω.

[F1]

The reversed triad (W;M1,M0) of an h-cobordism is again a compact smooth cobordism triad with collared boundary, the same manifold with the face labels exchanged (Smooth cobordism triad for Morse theory), and it is again an h-cobordism because the definition is symmetric in the two faces (h-Cobordism).

[F2]

Zero- and one-handles can be eliminated: a connected h-cobordism of dimension n+1, n≥5, with closed simply connected faces admits a presentation relative to its incoming boundary with no handles of index 0 or 1 (Zero- and one-handles are eliminated in a simply connected h-cobordism).

[F3]

Negating an adapted Morse function produces the dual handle decomposition, in which a k-handle of the reversed presentation becomes an (n+1−k)-handle of a presentation relative to M0, with attaching and belt spheres interchanged and the index ordered reversed (Handle duality from negating a Morse function, Dual handle decomposition).

[F4]

The low-index procedure removes only 0- and 1-handles and introduces only 3-handles; it preserves any upper index bound at least three (Zero- and one-handles are eliminated in a simply connected h-cobordism, proof step 5.1).

Proof

technique · direct
1.1F1F2given

By [F1] the reversed triad (W;M1,M0) is again an h-cobordism with the same dimension, and its faces are the same closed simply connected n-manifolds in the opposite order while W remains connected; hence the low-index elimination [F2] applies to the reversed triad and gives a presentation of W relative to M1 with no handles of index 0 or 1.

2.1F3step 1.1

Negate the Morse function of the reversed presentation and dualise by [F3]: a handle of index k in the presentation relative to M1 becomes a handle of index n+1−k in a presentation relative to M0, with attaching and belt spheres interchanged. Absent indices 0 and 1 therefore become absent indices n+1 and n, so the dual presentation relative to M0 has no handles of index n+1 or n.

3.1F2F3F4step 2.1given∎

To obtain the two exclusions simultaneously, first eliminate 0,1 relative to M0 by [F2]. Its reversed presentation has every index at most n−1. Apply the actual low-index procedure to that presentation relative to M1: by [F4] it deletes 0,1 and introduces only 3, so its maximum stays at most n−1, because n≥5. Reverse back by [F3]. The resulting original indices lie between 2 and n−1; both exclusions now hold in one presentation. No composition of two independently chosen presentations or face-fixing diffeomorphisms is being assumed.

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