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An admissibly normalized energy density is a probability measure

Statement

For every measure space (X,A,μ), measurable real energy Eθ, and parameter θ with 0<Zθ:=∫Xe−Eθ dμ<∞, the normalized measure Pθ(A):=Zθ−1∫Ae−Eθ(x) dμ(x),A∈A, is a probability measure on (X,A).

Statement references

Energy-based density and partition function supplies the notation Zθ and Pθ.

The measure with density f relative to μ identifies the nonnegative density integral as a measure.

Probability measures and probability spaces defines a probability measure by total mass one.

Facts & Assumptions

Given: A measure space (X,A,μ), a measurable real energy Eθ, and 0<Zθ<∞.

[F1]

Energy-based density and partition function: Pθ(A)=Zθ−1∫Ae−Eθ dμ and admissibility requires 0<Zθ<∞.

[F2]

The measure with density f relative to μ: if f≥0 is measurable, then A↦∫Af dμ is a measure.

[F3]

Probability measures and probability spaces: a measure on (X,A) with total mass one is a probability measure.

[F4]

The real exponential function and the number e by a power series and The exponential series converges absolutely for every real argument: the real exponential is the power-series sum exp⁡(t)=∑n≥0tn/n!, with infinite radius of convergence.

[F5]

The sum of a real power series is continuous at every point strictly inside its interval of convergence: a power-series sum is continuous at every point strictly inside its radius of convergence.

[F6]

A continuous map has Borel preimages of Borel sets: a continuous real map has Borel preimages of Borel sets.

[F7]

Composition with a Borel measurable outer map preserves measurability: a measurable map composed with a Borel measurable outer map is measurable.

Proof

1.1givenF1F2F4F5F6F7F8algebra

Define ϕ(t):=exp⁡(−t). By [F4], ϕ(t)=∑n≥0(−1)ntn/n! is a power-series sum with infinite radius, so [F5] makes ϕ continuous on R. Thus [F6] makes it Borel measurable, and [F7] with the measurable energy from [F1] makes x↦exp⁡(−Eθ(x)) measurable. Its values are positive by [F8], hence nonnegative. Put Mθ(A):=∫Ae−Eθ dμ. Now [F2] makes Mθ a measure and Mθ(X)=Zθ. Thus Pθ(∅)=Zθ−1Mθ(∅)=0. For any pairwise disjoint sequence (An)n≥0, [F2] and finite-sum homogeneity give Pθ(⋃n≥0An)=Zθ−1∑n≥0Mθ(An)=lim⁡N→∞∑n=0NZθ−1Mθ(An)=∑n≥0Pθ(An). Therefore Pθ is a measure.

2.1F1F3step 1.1algebra∎

Its total mass is Pθ(X)=Zθ−1Mθ(X)=1, so [F3] makes Pθ a probability measure.

Depends on

Used by

Nothing in the library uses this result yet.

Cited to discharge well-definedness by Energy-based density and partition function.

Dependency tree · two levels

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Sources