Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passverified 2026-08-10 (gpt-5.6-terra-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The exponential series converges absolutely for every real argument

Statement

For every real xx, the series n0xn/ι(n!)\sum_{n\ge0}x^n/\iota(n!) converges absolutely. Its power-series radius is therefore ++\infty.

Facts & Assumptions

Proof

technique · direct
1.1

If x=0x=0, the series is 1+0+0+1+0+0+\cdots and converges absolutely. Hence assume x0x\ne0. Choose N1N\ge1 with ι(N)>2x\iota(N)>2|x|. For nNn\ge N, the absolute terms an=xn/ι(n!)a_n=|x|^n/\iota(n!) are positive and satisfy an+1/an=x/ι(n+1)<1/2a_{n+1}/a_n=|x|/\iota(n+1)<1/2.

L1L3choose
2.1

Thus aN+jaN2ja_{N+j}\le a_N2^{-j} by induction, and the tail is dominated by a convergent geometric series.

step 1.1L2
3.1

The zero case from step 1.1 and, when x0x\ne0, adding the finite initial segment to the convergent tail prove absolute convergence for arbitrary xx. Hence every nonnegative radius works and the radius is ++\infty.

step 1.1step 2.1L2

Depends on

Used by

Cited to discharge well-definedness by The real exponential function and the number e by a power series.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 102 results over 22 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources