Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A specialization is represented by a complete DVR trait

Statement

Assume AC. Let S be locally Noetherian and s0∈{s1}‾. There is a morphism Spec⁡R→S, with R a Noetherian DVR, carrying its generic point to s1 and its closed point to s0. Replacing R by its completion preserves these two images. One can also arrange that the complete DVR has algebraically closed residue field, allowing extension of both residue and fraction fields. If s0=s1, a constant trait suffices.

This is a new local support item for A911. The assertion concerns the selected specialization of underlying points. Identification with particular geometric points and paths is additional data, handled by the geometric field and basepoint support items; no independence of that data is asserted.

Facts & Assumptions

Given: AC, S, and the selected pair s1,s0.

[F1]

A local domain admits a dominating valuation overring under AC (A local domain has a dominating valuation overring, The Axiom of Choice). Algebraic closures exist under AC (Assuming Choice, every field has an algebraic closure).

[F2]

A prime minimal over a nonzero principal ideal in a Noetherian domain has height one; integral extensions satisfy lying over (Krull's height theorem, Lying over for integral ring maps).

[F3]

A normal one-dimensional Noetherian local domain is a DVR (Equivalent characterizations of a DVR).

[F4]

Noetherian local completion is local, Noetherian and faithfully flat, preserves the residue field, and is separated. Krull intersection gives injectivity for a local domain (Completion of a Noetherian local ring is local with the same residue field, The completion of a Noetherian ring is flat, The Krull intersection is the (1−a)-torsion submodule, and it vanishes in the Jacobson-radical case).

Proof

1.1F1F2givenchooseconstruct

Choose a Noetherian affine neighbourhood Spec⁡A of s0. It contains s1, since an open set contains every generalization of each of its points. Write their primes as p⊆q and set B=(A/p)q/p. This is a local Noetherian domain whose generic and closed points map to s1,s0. If they coincide, take R=κ(s0)⟦t⟧ and the constant map. Otherwise B is not a field. Let V be a valuation ring of Frac⁡B dominating B, by [F1]. For generators a1,…,ar of its maximal ideal choose ar of smallest valuation. Then C=B[a1/ar,…,ar−1/ar]⊂V is Noetherian and mBC=arC is proper. A prime n minimal over it has height one by [F2] and contracts to mB. Thus D=Cn is a one-dimensional Noetherian local domain dominating B, with the same fraction field.

2.1step 1.1algebra

We give the needed normalization argument even when D is not excellent. Put F=Frac⁡D and let M⊂F be any D-submodule. For 0≠x∈mD, put ℓ=length⁡D(D/xD)<∞; finiteness follows since its only prime is maximal and the quotient is Noetherian of dimension zero. If N⊂F is nonzero and finite over D, clear denominators so N⊂D. The torsion finite module D/N has finite length and is killed by some power xc, so xcD⊂N⊂D. Since multiplication by x is injective, length⁡(N/xnN)=nlength⁡(N/xN). For n≥c the inclusions imply xn+cD⊂xnN⊂N⊂D and xnN⊂xcD⊂N, giving (n−c)ℓ≤length⁡(N/xnN)≤(n+c)ℓ. Divide by n and let n increase to obtain length⁡(N/xN)=ℓ. Any finite strict chain in M/xM can be witnessed by finitely many elements of M; the submodule N they generate has a chain at least as long in N/xN. Thus length⁡(M/xM)≤ℓ.

3.1F2F3step 1.1step 2.1chooseconstruct

Let E be the integral closure of D in F. For a nonzero ideal I⊂E, a nonzero y∈I can be written a/b with a,b∈D nonzero; hence 0≠a=by∈I∩D. Step 2.1 with M=E says E/aE has finite length (the unit case gives zero). Therefore I/aE is finite over D, and lifts of its generators together with a generate I over E. Every ideal of E is finite, so E is Noetherian. By lying over choose a prime r over mD. Its height is one: after inverting D∖{0} the integral closure is F, so the only prime contracting to zero is zero; primes above the maximal ideal cannot be strictly comparable, since localizing and then quotienting by the lower prime gives an integral algebraic domain over a field, hence a field. Thus R=Er is normal local Noetherian of dimension one and is a DVR by [F3]. Its local inclusion B⊂R⊂F gives the required two point images.

4.1F4step 3.1algebra

Let π be a uniformizer of R. By [F4], R^ is Noetherian local with maximal ideal (π) and the same residue field; flatness makes π a nonzerodivisor. Each nonzero element lies in a largest power (πn), because the completion is separated, and is πn times a unit. Products of two such elements are nonzero, so R^ is a domain, and this description is the DVR property. The map R→R^ is injective by [F4]; its generic point contracts to zero and its closed point to (π). Both images in S are therefore unchanged.

5.1F1F4step 4.1chooseconstruct∎

To make the residue field algebraically closed, fix an algebraic closure k‾ of k=R/(π) and well order its elements, using AC. At a successor stage, given a DVR T with uniformizer π and residue subfield kT⊂k‾, take the monic minimal polynomial of the next element over kT, lift its coefficients to T, and form T′=T[z]/(P). This is finite free over T, and its reduction modulo π is the required residue field extension. Every maximal ideal lies over (π), so T′ is local with maximal ideal (π). It is Noetherian; π is a nonzerodivisor by freeness and the π-adic intersection is zero by Krull intersection. As in step 4.1 every nonzero element is a unit times a power of π, proving that T′ is a DVR and that T→T′ is injective. At limit stages take unions. Every nonzero element is still a unit times a power of the same π, and every nonzero ideal has an element of minimal exponent, so is principal. The union is therefore a Noetherian DVR with residue field k‾. Its completion is again a DVR by step 4.1, with residue field k‾. All extensions are local and injective, preserving the point images. AC is used for the valuation overring, algebraic closure and the transfinite choices, and is inherited from the listed suppliers.

Depends on

Used by

Dependency tree · two levels

56 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources