Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-sol)audited 2026-09-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A field has only the zero ideal and itself, hence is Noetherian

Statement

Let K be a field (Field). Then the only ideals of K are the zero ideal (0) and K itself (Left, right and two-sided ideals, The ideal generated by a subset and principal ideals); consequently every ideal of K is finitely generated, and K is a Noetherian ring (Left and right Noetherian rings, Noetherian modules: every submodule is finitely generated). No choice principle is used.

Facts & Assumptions

Given: A field K and an ideal I⊆K.

[F1]

Field: in a field every nonzero element a has a multiplicative inverse a−1 with a a−1=1, and 1≠0.

[F2]

Left, right and two-sided ideals: an ideal I⊆K is an additive subgroup closed under multiplication by elements of K, so ra∈I for all r∈K, a∈I; hence I=K as soon as 1∈I.

[F3]

The ideal generated by a subset and principal ideals: for a∈K the ideal (a) is the intersection of all ideals containing a; in particular (0)={0} is generated by 0 and K=(1) is generated by 1, so both are generated by a single element.

[F4]

Left and right Noetherian rings and Noetherian modules: every submodule is finitely generated: a ring is Noetherian when its left regular module is Noetherian, meaning that every left submodule is finitely generated. For the commutative field K, these submodules are precisely its ideals.

Proof

technique · direct
1.1F1F2given

A nonzero ideal is everything: if I≠(0) choose a∈I with a≠0; by [F1] a is invertible with inverse a−1∈K, and since I is closed under multiplication by elements of K, 1=a−1a∈I by [F2]; then x=x⋅1∈I for every x∈K by [F2] again, so I=K.

2.1step 1.1F3

The ideal list: by step 1.1 every ideal of K is either (0) or K; the zero ideal is generated by the single element 0 and K=(1) is generated by the single element 1, so every ideal of K is finitely generated.

3.1step 2.1F4given∎

Conclusion: by step 2.1 every ideal of K is finitely generated, so [F4] makes K a Noetherian ring. The argument used only the field axioms, the ideal axioms and the two-element list of ideals, so it invokes no choice principle.

Depends on

Used by

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