How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Finite normalization commutes with principal localization
Statement
Let be a field, let be a finite-type integral domain over , let be the integral closure of in , and let . Then the integral closure of the principal localisation inside the field is exactly the localisation , and is a finite -module.
Facts & Assumptions
Given: a field , a finite-type integral domain over , its integral closure in , and an element .
Let be a homomorphism of commutative rings, multiplicative and : if is integral over then is integral over . Moreover, if is a domain, , is a field extension of and is the integral closure of in , then the integral closure of in is exactly (Integrality and integral closure commute with localisation, Multiplicative subsets and the localisation as equivalence classes of fractions).
For a commutative ring and the powers form a multiplicative subset, and the principal localisation is with elements written ; the element becomes a unit, and an element is zero exactly when for some (Principal localisation , Multiplicative subsets and the localisation as equivalence classes of fractions).
The integral closure of a finite-type domain over a field in its fraction field is a finite module over the domain (A finite-type domain over a field has finite normalization, Subalgebra generated by a subset, algebras of finite type, and module-finite algebras, Integral closure in an extension ring and integrally closed domains).
If is a domain and , then is a domain containing and the identity on exhibits as a field containing , and : each element of is a fraction of elements of , hence lies in , while each with , , equals with (The field of fractions of an integral domain, Zero divisor, and integral domain: a commutative ring with and no zero divisors, Principal localisation ).
If is a finite -module with generators and , then is a finite -module: every element of is with , and (Module finiteness is transitive along a tower of algebras, Generated submodule, cyclic and finitely generated modules, module basis and free module, Principal localisation ).
Proof
The element is nonzero in the domain , so the multiplicative subset is contained in by [L2] and [L4]. By [L3] the integral closure of in is a finite -module. The localisation is a domain containing , and by [L4] the field contains and equals its fraction field, so the phrase "the integral closure of inside " is computed inside a field extension of .
Applying the third clause of [L1] with the domain , the multiplicative subset , the field and : the integral closure of in is exactly . This is a genuine equality inside the fixed field , not an isomorphism chosen afterwards, so it is canonical.
By [L5], applied to the finite generating list of the -module from step 1.1, the localisation is generated as an -module by the finitely many elements , so is a finite -module. Combined with step 2.1, the integral closure of inside is , a finite -module. If is a unit of , then contains and , so the statement reduces to ; the hypothesis is exactly what makes a subset of , and it is used nowhere else.
Depends on
- A finite-type domain over a field has finite normalization
- Integrality and integral closure commute with localisation
- Principal localisation $R_f=\{1,f,f^2,\ldots\}^{-1}R$
- Multiplicative subsets and the localisation $S^{-1}R$ as equivalence classes of fractions
- The field of fractions $\operatorname{Frac}(D)=(D\setminus\{0\})^{-1}D$ of an integral domain
- Zero divisor, and integral domain: a commutative ring with $1 \ne 0$ and no zero divisors
- Subalgebra generated by a subset, algebras of finite type, and module-finite algebras
- Module finiteness is transitive along a tower of algebras
- Generated submodule, cyclic and finitely generated modules, module basis and free module
- Integral closure in an extension ring and integrally closed domains
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
39 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Stacks Project, Lemma 10.36.11 (integral closure commutes with localization) (standard reference, not scraped)
- J. S. Milne, A Primer of Commutative Algebra, §6, §17 (standard reference, not scraped)