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Criterion for a scheme to represent an fppf quotient sheaf

Statement

Assume the Axiom of Choice for the represented-sheaf and geometric suppliers used on this page. Let k be a field, let s,t:R→U be a pre-relation on k-schemes with fppf quotient sheaf U/R (Quotient sheaves and representable quotients for pre-relations and group actions), and let q:U→M be a morphism to a k-scheme M. Assume: (1) q∘s=q∘t; (2) q induces a surjection of fppf sheaves hU→hM (for instance, q is faithfully flat and locally of finite presentation); (3) the morphism (t,s):R→U×MU (Fibre product of schemes) induces a surjection of fppf sheaves hR→hU×MU (for instance (t,s) is faithfully flat and locally of finite presentation). Then M represents the quotient sheaf U/R.

Facts & Assumptions

Given: AC, the pre-relation s,t:R→U, the fppf quotient sheaf U/R, and a morphism q:U→M satisfying (1), (2) and (3).

[F1]

The naive quotient presheaf PU/R sends T to U(T) modulo the relation generated by R(T), and U/R is its sheafification: the morphism PU/R→U/R is initial among morphisms from PU/R to fppf sheaves, in particular U/R is an fppf sheaf (Quotient sheaves and representable quotients for pre-relations and group actions).

[F2]

Represented scheme functors are fppf sheaves. In particular, if a morphism X→Y is faithfully flat and locally of finite presentation, then hX→hY is a surjection of fppf sheaves (Scheme morphisms satisfy fppf descent, Faithfully flat scheme morphism, Locally finite presentation morphisms).

[F3]

The fibre product U×MU represents the functor T↦{(u,u′)∈U(T)×U(T):q(u)=q(u′)}, naturally in T (Fibre product of schemes).

Proof

Given: AC, the pre-relation s,t:R→U, the fppf quotient sheaf U/R, and q:U→M satisfying (1), (2) and (3).

1.1F1F2givenconstruct

For every k-scheme T the map U(T)→M(T), u↦q(u), is constant on each generating pair (s(x),t(x)) of the relation on U(T) by (1), hence constant on the equivalence relation it generates, so it descends to a map PU/R(T)→M(T); these maps are natural in T and define a morphism of presheaves PU/R→hM. By [F2] the functor hM is an fppf sheaf, so the universal property in [F1] factors this morphism uniquely through a morphism φ:U/R→hM.

1.2F1construct

Every section of U/R is locally represented by a section of U. Let V(T)⊆(U/R)(T) be the set of sections s for which there are an fppf covering {Ti→T} and elements ui∈U(Ti) whose images in (U/R)(Ti) equal the restrictions of s. Restrictions of such sections lie in V, so V is a subpresheaf of U/R; and V is a sheaf, because an fppf covering of each member of an fppf covering of T composes to an fppf covering of T. Since U(T)→PU/R(T) is surjective for every T, the canonical morphism PU/R→U/R takes values in V, so there is a factorization PU/R→V through the inclusion V↪U/R. Applying the initiality in [F1] to the target sheaf V and to the target sheaf U/R shows that the composite U/R→V↪U/R is the identity: both maps make the triangle from PU/R commute, and such a map is unique. Therefore V=U/R, which is the claim.

2.1F1F2F3givenstep 1.1construct

The morphism φ is surjective as a map of fppf sheaves. Let T be a k-scheme and m∈M(T)=hM(T). By (2) there are an fppf covering {Ti→T} and ui∈U(Ti) with q(ui)=m∣Ti. For every pair i,j, the restrictions ui∣Tij and uj∣Tij have the same image in M(Tij), so by [F3] they define a section of hU×MU(Tij). Hypothesis (3) lifts this section, after an fppf refinement of Tij, to r with (t(r),s(r))=(uj,ui). Thus [ui] and [uj] agree in the quotient presheaf locally on Tij and hence agree in its sheafification U/R on Tij. They are therefore a matching family in the sheaf U/R, so glue to s∈(U/R)(T). Step 1.1 gives φ([ui])=q(ui)=m∣Ti; since hM is a sheaf, φ(s)=m. Thus every section of hM lies in the image of φ.

2.2F1F3givenstep 1.2construct

The morphism φ is injective as a map of presheaves. Let ξ,ξ′∈(U/R)(T) satisfy φ(ξ)=φ(ξ′)=m. By step 1.2 there are an fppf covering {Ti→T} of T and elements ui,ui′∈U(Ti) with ξ∣Ti=[ui] and ξ′∣Ti=[ui′]. Then q(ui)=φ([ui])=m∣Ti=φ([ui′])=q(ui′), so (ui′,ui) is a Ti-point of U×MU by [F3]. Hypothesis (3) provides, after refining the covering, an element ri∈R(Ti) with (t,s)(ri)=(ui′,ui), that is t(ri)=ui′ and s(ri)=ui. Then (s(ri),t(ri))=(ui,ui′) is a generating pair of the relation defining PU/R(Ti), so [ui]=[ui′] in (U/R)(Ti). Hence ξ and ξ′ agree on the members of an fppf covering, and separatedness of the sheaf U/R forces ξ=ξ′.

3.1F1F2givenstep 2.1step 2.2∎

A morphism of fppf sheaves that is surjective and injective on sections is an isomorphism, so steps 2.1 and 2.2 show that φ:U/R→hM is an isomorphism; hence hM≅U/R naturally and M represents the quotient sheaf U/R. For the parenthetical instances, if q is faithfully flat and locally of finite presentation then hU→hM is a surjection of fppf sheaves by [F2], and the same argument with X=R and Y=U×MU gives the second instance; this finishes the proof.

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Dependency tree · two levels

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