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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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The general Ito integral is well defined

Statement

Assume the Axiom of Choice and the standing hypothesis (H) of Elementary predictable Brownian integrands. Let H be a predictable process on [0,T] with E0TH2ds<, and let (Hn) and (Kn) be two sequences of bounded elementary predictable integrands converging to H in L2(dtP). Then limnIT(Hn)=limnIT(Kn)in L2(P), so the integral 0THdB of Ito integral for square-integrable predictable processes does not depend on the approximating sequence. If H is any predictable process with H=H (dtP)-almost everywhere and finite energy, then 0THdB=0THdB almost surely; the integral is a function of the (dtP)-class alone.

Facts & Assumptions

Given: AC, the standing hypothesis (H), a finite-energy predictable H, two elementary approximating sequences HnH and KnH in L2(dtP), and a predictable H with H=H almost everywhere and finite energy.

[F1]

For elementary predictable G,G on a common refinement, IT(G)IT(G)=IT(GG) identically and E(IT(G)IT(G))2=E0T(GG)2ds=GGL2(dtP)2. Ito isometry for elementary integrands Ito integral of an elementary predictable process

[F2]

Each of the sequences IT(Hn) and IT(Kn) is Cauchy in the complete space L2(P) and therefore has an L2(P) limit. The construction designates the limit obtained from one admissible approximating sequence as 0THdB; equality with the limit from every other sequence is what is proved below. Ito integral for square-integrable predictable processes

[F3]

The L2 triangle inequality and the identities UV2=0    U=V almost surely hold on the quotient space. The Lp norm descends to the quotient and makes Lp a normed space for 1p

[F4]

The elementary integral of the difference is the difference of the elementary integrals on a common refinement, and the class of a bounded elementary integrand depends only on its (dtP)-class. Ito integral of an elementary predictable process Elementary Ito integrals do not depend on step representation

[F5]

AC is declared for the ambient interfaces; the argument below only uses the two given sequences and the metric algebra of L2. The Axiom of Choice

Proof

technique · direct
1.1

Pass to a common refinement of the two elementary representations at each index and use [F1]: IT(Hn)IT(Kn)22=HnKnL2(dtP)2, a finite quantity depending only on the two indices.

F1given
1.2

The triangle inequality gives HnKn2HnH2+HKn20 as n, because both approximating sequences converge to H.

F3given
1.3

If H=H almost everywhere, then every approximating sequence for H is an approximating sequence for H: HnH2HnH2+HH2=HnH20, and likewise in the other direction.

F3given
2.1

By step 1.1 and step 1.2 the difference of the two sequences of elementary integrals converges to 0 in L2(P), while by [F2] each sequence converges; two convergent sequences with difference tending to 0 have the same limit, and by [F3] the limits agree as L2(P)-classes, that is, almost surely.

F2F3step 1.1step 1.2
3.1

Consequently the class 0THdB is independent of the approximating sequence; and by step 1.3, replacing H by an almost-everywhere equal H keeps the same admissible sequences and hence the same limit, so 0THdB=0THdB almost surely. Only the two given sequences are used, and AC enters only as the declared ambient interface [F5].

F4F5step 1.3step 2.1

Source notes

Van der Vaart, Definition 5.25 and Theorem 5.26, performs the same two descents: independence of the approximating sequence for a fixed integrand, and invariance under changing the integrand on a product-null set. Both are isometry statements for elementary differences, so no pathwise argument is involved.

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