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The grand maximal function is pointwise dominated by a tangential maximal function
Statement
Assume Countable Choice. Let , and let with . Then there are and such that for every and every , where is the grand maximal function of Grand maximal test class of order N and the grand maximal function and is the tangential maximal function . Consequently for every , both sides extended values.
Facts & Assumptions
Given: Countable Choice, , , with , .
Deconvolution: for every and every choice of positive integer parameters there are and with in and (Deconvolution of a Schwartz function along the dyadic dilates of a fixed kernel); here is the norm . The supplier's weight and this weight satisfy ; absorb in .
If and , then whenever in the sense of the decomposition of [F1]: apply Schwartz parameter pairing and integral interchange to . Each Schwartz seminorm of this family is bounded by , an integrable function because is Schwartz. The interchange proves the identity. Applying continuity of to the reflected translate of each partial sum in [F1] also justifies passage to the series; the subsequent nonnegative estimates apply to finite sums first, then to their limit.
The translated kernel satisfies for , and if then for (Grand maximal test class of order N and the grand maximal function, Schwartz space and its seminorms).
Proof technique: insert the dyadic deconvolution identity and sum the rapidly decaying coefficients.
Proof
Single-kernel estimate. Choose integers and (for example, and ), and apply [F1] with these parameters, obtaining . By the smaller-scale clause of [F1], decrease if necessary so that . Take an integer . Fix , and ; write the deconvolution of [F1] and set . If , the desired estimate is immediate. Otherwise, by [F2], where we used the definition of with the displacement at scale . Substituting and using gives since , makes integrable, and [F1] gives . Also by the choice of . The series converges because , so with independent of .
Aperture. For and with write , so , and let ; then : both equal and . By [F3], , so the kernel satisfies ; the argument of step 1.1 uses only this bound on the kernel and the deconvolution of [F1] with the kernel , so it applies verbatim to and gives . Since and , multiplying by gives . Taking the supremum over , and gives . The statement follows by monotonicity of the integral; for it is the pointwise bound.
Conclusion. Step 1.1 controls a single test kernel by the tangential maximal function with a rapidly convergent deconvolution expansion, and step 2.1 removes the aperture restriction by translating the kernel; the class is then dominated pointwise. This proves the lemma.
Depends on
- Grand maximal test class of order N and the grand maximal function
- Radial and nontangential maximal functions of a tempered distribution
- Convolution of a tempered distribution with a schwartz function
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Deconvolution of a Schwartz function along the dyadic dilates of a fixed kernel
- Dilations and their normalisations preserve Schwartz space, with scaling identities
- Schwartz space and its seminorms
- Schwartz parameter pairing and integral interchange
Used by
Dependency tree · two levels
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Sources
- David Cruz-Uribe SFO, Li-An Daniel Wang, Variable Hardy Spaces, arXiv:1211.6505 (2012) (standard reference, not scraped)
- Marcin Bownik, Anisotropic Hardy Spaces and Wavelets, Memoirs of the American Mathematical Society 164 (2003), no. 781 (standard reference, not scraped)