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The family consisting of and co- has the Erdős–Hajnal property
Statement
The finite forbidden family has the Erdős–Hajnal property.
Facts & Assumptions
Given: The graphs and the graph co-.
The graph has the Erdős–Hajnal property (The graph has the Erdős-Hajnal property).
The graph has the Erdős–Hajnal property (The five-vertex path and its complement have the Erdős-Hajnal property).
The Erdős–Hajnal property passes to a hereditary subclass (The Erdős–Hajnal property and each of its constants pass to hereditary subclasses).
Huang--Ju--Zhou, Corollary 1.8, states the following leaf/co-leaf transfer. Let be a finite family, let have a leaf , and let have a co-leaf . If both families obtained from by replacing, respectively, by and by have the Erdős--Hajnal property, then has the Erdős--Hajnal property.
Proof
The class of -free graphs is a hereditary subclass of the class of -free graphs, and the class of -free graphs is a hereditary subclass of the class of -free graphs. Thus [F1]--[F3] give the Erdős–Hajnal property for both families, for every .
Fix and suppose that has the property. In , deleting the leaf of gives . The vertex is a leaf of , so it is a co-leaf of co-, and deleting it from co- leaves . Hence the two modified families in [F4] are exactly and .
Step 1.2, the induction hypothesis, and the second base family from step 1.1 let [F4] yield the property for .
Starting with and repeating step 2.1 through proves the property for .
Depends on
- The graphs $H_0,H_1,\ldots,H_5$
- The $E$-graph and co-$E$
- $H$-free and $\mathcal F$-free graphs under the induced-subgraph convention
- The Erdős–Hajnal property and an Erdős–Hajnal constant for a hereditary graph class
- The graph $H_0$ has the Erdős-Hajnal property
- The five-vertex path and its complement have the Erdős-Hajnal property
- The Erdős–Hajnal property and each of its constants pass to hereditary subclasses
Used by
Dependency tree · two levels
19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Huang, Ju, and Zhou, Erdős-Hajnal beyond the five-vertex path, Lemma 6.3 (standard reference, not scraped)
- Huang, Ju, and Zhou, Erdős-Hajnal beyond the five-vertex path, Corollary 1.8 (standard reference, not scraped)