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LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
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Interior decay of Neumann modes and kernel forward continuity

Statement

Assume the Axiom of Choice and Countable Choice. Fix a smooth bounded connected domain Ω, an open Ω′⋐Ω, and 0<m≤1≤M<∞. Let γ,γ0 range over all measurable conductivities between m and M equal to one outside Ω′. Let (ej,λj) be the mean-zero boundary spectral basis and put wj=1+λj. There is p∈(2,4) such that for every L>0, ∥∇uγ,ej∥Lp(Ω′)≤CLwj−L. Put q=p/(p−2)>2. For any fixed smoothing exponent r≥0, the difference (Rγ−Rγ0)(1−Δ∂Ω)−r/2, extended to kill constants, is Hilbert–Schmidt and satisfies ∥(Rγ−Rγ0)(1−Δ∂Ω)−r/2∥HS≤Cr∥γ−γ0∥Lq(Ω). It also satisfies the same bound with the coefficient L∞ norm in place of Lq. Constants depend only on the displayed fixed geometry, ellipticity and exponents.

Facts & Assumptions

Given: the fixed domain, collar, conductivity bounds and basis in the Statement.

[F1]

A harmonic function with zero normal derivative in a fixed smooth collar has every integer boundary Sobolev norm bounded by its collar H1 norm, by the explicit boundary difference-quotient induction in step 1.2 of the collar lemma. The spectral and chart half-order norms are equivalent. (Uniform NtD estimates from a fixed harmonic boundary collar)

[F2]

The interior higher-integrability estimate is uniform for measurable conductivities: on nested fixed domains, ∥∇u∥Lp(U)≤C∥∇u∥L2(V) for some p>2; the proof permits p<4. (Uniform interior higher integrability for conductivity solutions)

[F3]

Weak Neumann solutions obey the uniform energy estimate, and bounded coercive energy forms solve every bounded volume-gradient functional by Lax–Milgram. (Mean-zero weak Neumann problem for uniformly elliptic conductivities, The Lax--Milgram theorem)

[F4]

For every a>(d−1)/2, ∑jwj−a<∞. (Boundary spectral counting and Sobolev scale)

[A1]

The Axiom of Choice and Countable Choice are assumed at those weak-solution, spectral, Sobolev and harmonic-analysis interfaces. (The Axiom of Choice, The Axiom of Countable Choice (ACω))

Proof

Given: the fixed data in the Statement.

1.1A1F1F3givenconstruct

Cover Ω′‾ by finitely many balls Bℓ whose concentric doubled balls 2Bℓ have closure in Ω, and put V=⋃ℓ2Bℓ. Let v∈L2(V;Rd). On the volume-mean-zero H1 space, [F3] solves ∫Ω∇z⋅∇φ=∫Vv⋅∇φ, with ∥z∥H1≤C∥v∥2. This solution is harmonic with zero Neumann data in the fixed boundary collar. By [F1], its boundary trace has spectral HΔk norm at most Ck∥v∥2 for every integer k. Testing this equation with the background Neumann solution u1,ej, and that solution's equation with z, yields ∣∫Vv⋅∇u1,ej∣=∣⟨ej,z∣∂Ω⟩∣≤Ckwj−k/2∥v∥2. Taking the L2 dual supremum proves ∥∇u1,ej∥L2(V)≤Ckwj−k/2. No boundary regularity for a negative-order prescribed flux has been assumed in this argument.

2.1F2step 1.1givenalgebra

The correction w=uγ,ej−u1,ej satisfies ∫γ∇w⋅∇φ=∫Ω′(1−γ)∇u1,ej⋅∇φ. Coercivity and step 1.1 give ∥∇w∥L2(Ω)≤C∥∇u1,ej∥L2(Ω′)≤Ckwj−k/2. Adding the background gradient on V gives ∥∇uγ,ej∥L2(V)≤Ckwj−k/2. Apply [F2] on each smooth ball 2Bℓ, restricted to Bℓ, and sum the finitely many bounds to obtain the stated rapid Lp(Ω′) decay, choosing k≥2L. All domains and constants were fixed before choosing γ or j.

3.1step 2.1givenalgebra

The two weak Neumann equations, tested with the opposite solutions and subtracted, give bij=⟨(Rγ−Rγ0)ej,ei⟩=∫Ω′(γ0−γ)∇uγ,ej⋅∇uγ0,ei‾. Hölder with 1/q+2/p=1 and step 2.1 imply ∣bij∣≤CL∥γ−γ0∥q(wiwj)−L. Alternatively, the two rapid L2(V) bounds from that step and the coefficient supremum norm imply the identical bound with ∥γ−γ0∥∞. The conjugates and sign are consistent with the self-adjoint weak energy form; only the absolute value is used.

4.1F4step 3.1algebra∎

In the boundary basis the smoothed matrix is bijwj−r/2. Choose L with 2L>(d−1)/2. By [F4], ∑i,j∣bij∣2wj−r≤CL2∥γ−γ0∥q2(∑iwi−2L)(∑jwj−2L−r)<∞, with the asserted bound after taking the square root. A matrix with this sum finite defines its Hilbert–Schmidt operator: finite column sums converge in squared Hilbert–Schmidt norm and coincide with the given bounded operator on every finite spectral sum, hence on the dense span. The same proof uses the supremum-norm version of step 3.1. Extending by zero on constants preserves these norms.

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