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Mean-zero weak Neumann problem for uniformly elliptic conductivities
Statement
Assume the Axiom of Choice and Countable Choice. Let , let be nonempty, bounded, connected and , and let satisfy almost everywhere. Let be the complex trace quotient and write . Let denote the continuous conjugate-linear dual of . For each there is a unique weak solution class satisfying The resulting solution operator is bounded. Its unique representative whose boundary trace has surface mean zero solves the same weak equation. In particular, for with , the functional is admissible and defines the mean-zero Neumann-to-Dirichlet map on mean-zero fluxes.
Statement references
Facts & Assumptions
Given: the Axiom of Choice and Countable Choice, , , and as in the statement.
The hypotheses stated above give a real coefficient with almost everywhere; these bounds make the weak form bounded and coercive. No narrower conductivity class is used for this estimate.
On a bounded connected extension domain, subtracting the volume mean gives . (Poincare-Wirtinger on bounded connected extension domains by Rellich compactness)
The trace is bounded from to and the trace quotient norm is equivalent to the boundary norm; constants correspond under the quotient identification. (Boundary trace quotient and chart norm equivalence)
A bounded coercive sesquilinear form on a Hilbert space and a bounded conjugate-linear functional have a unique weak solution with norm at most the functional norm divided by the coercivity constant. (The Lax--Milgram theorem)
Every bounded domain is a Sobolev extension domain, and its compact boundary has finite positive surface measure. (Bounded C^k domains admit integer-order Sobolev extension, Surface integration on compact C1 hypersurfaces, Chart and partition independence of surface measure)
The Axiom of Choice is used at the Poincaré and trace interfaces. (The Axiom of Choice)
Countable Choice is used at the Lax–Milgram interface. (The Axiom of Countable Choice ())
Proof
Given: The data in the statement.
Let , a closed Hilbert subspace of . By [F2], on , where . By [F1], the form is bounded on and . Thus it is bounded and coercive on .
Define for . By [F3], the quotient trace norm of is at most , so ; hence is bounded on . Applying [F4] to step 1.1 gives a unique with for every .
For arbitrary write with and . Gradients are unchanged by adding , and acts on the trace quotient by constants, so the equation for on implies it for every . If represents another solution class, put . Subtracting the two weak equations gives for all ; setting and using coercivity from step 1.1 gives . Thus the solution is unique modulo constants.
The estimate in [F4] and step 2.1 give . The bounded trace map [F3] therefore makes the solution class in a bounded linear function of . By [F5], the compact smooth boundary has finite positive surface measure. Subtracting the surface mean of selects one representative with boundary mean zero; this constant shift preserves the weak equation and is the only such shift. For mean-zero , Cauchy–Schwarz and the trace bound show is continuous, and its zero mean makes it independent of the representative modulo constants. This proves the final assertion.
Depends on
- The Axiom of Choice
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Calderón admissible conductivity classes
- Surface integration on compact C1 hypersurfaces
- Boundary trace quotient and chart norm equivalence
- Chart and partition independence of surface measure
- Bounded C^k domains admit integer-order Sobolev extension
- The Lax--Milgram theorem
- Poincare-Wirtinger on bounded connected extension domains by Rellich compactness
Used by
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Sources
- Luca Rondi, On the regularization of the inverse conductivity problem with discontinuous conductivities (standard reference, not scraped)
- Richard S. Laugesen, Linear Analysis and Partial Differential Equations (standard reference, not scraped)