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The L-genus is an oriented rational bordism ring homomorphism

Statement

Assume AC. The L-genus The total L-class and the L-genus of a smooth manifold satisfies: (1) L[M⊔N]=L[M]+L[N] and L[−M]=−L[M] for closed oriented manifolds of dimension divisible by four; (2) L[M]=0 whenever M=∂W for a compact oriented smooth manifold W; (3) L[M×N]=L[M]L[N] for closed oriented M4a,N4b. Consequently the L-genus is well defined on oriented bordism classes, is additive, and extends to a unital Q-algebra homomorphism L:Ω∗SO⊗Q⟶Q, assigning to each closed oriented 4k-manifold its L-genus and the value 0 in dimensions not divisible by four.

Facts & Assumptions

Given: AC; closed oriented smooth manifolds in the dimensions named; the L-genus of The total L-class and the L-genus of a smooth manifold.

[F1]

L[M]=⟨Lk(TM),[M]⟩ in dimension 4k, and Lk is a homogeneous weight-4k polynomial Lk=∑∣J∣=kcJpJ with cJ∈Q, so L[M]=∑cJpJ[M]; for dimensions not divisible by four the value is declared 0 (The total L-class and the L-genus of a smooth manifold, Pontryagin numbers of a closed oriented manifold).

[F2]

The bundle-level total L-class is stable, multiplicative and natural, and equals 1 for trivial bundles (The L-polynomials are well defined and form a multiplicative, natural and stable sequence).

[F3]

Every Pontryagin number of a closed oriented boundary vanishes: pJ[∂W]=0 (Oriented boundaries have zero Pontryagin numbers, All characteristic numbers vanish on null-cobordant manifolds).

[F4]

The fundamental class of a disjoint union is componentwise, [M⊔N]=[M]+[N], and reversing the orientation negates it, [−M]=−[M]; the class of each component of a disjoint union is computed on that component (Fundamental class of a compact oriented manifold, The singular homology of a disjoint union is the direct sum).

[F5]

The tangent bundle of a product splits canonically: T(M×N)≅TM⊞TN for the product smooth structure (Canonical tangent and cotangent splittings for products).

[F6]

[M×N]=[M]×[N] for closed oriented manifolds with the product orientation (The fundamental class of a product is the cross product of the fundamental classes).

[F7]

The Kronecker pairing is multiplicative under cross products: ⟨α×β,[M]×[N]⟩=⟨α,[M]⟩⟨β,[N]⟩ (The Kronecker pairing is multiplicative under cross products).

[F8]

Characteristic numbers of products expand over the Kunneth splitting, so pairing the degree-4k part of L(TM)L(TN) with [M×N] gives the product of the factor evaluations (Characteristic numbers of products satisfy the Whitney-sum and Kunneth product formulas).

[F10]

Closed oriented manifolds have rational cohomology zero above their dimension (Finite generation from cap with a finite fundamental cycle).

[F9]

Oriented cobordism classes form the graded ring Ω∗SO under disjoint union and Cartesian product, with unit the class of a positively oriented point, and Ω∗SO⊗Q is its rationalization; a null-cobordant manifold is the boundary of a compact oriented manifold (Unoriented and oriented bordism groups, Cartesian product makes bordism a graded ring, Product boundary formula for oriented manifolds, Null-cobordant closed manifolds).

Proof

technique · direct; reduce each of the three bordism axioms to the bundle-level multiplicativity and the product formulas
1.1givenF1F2F4algebra

Additivity and orientation: let M,N be closed oriented 4k-manifolds. The restriction of the tangent bundle of M⊔N to M is TM and to N is TN, so the polynomial Lk(T(M⊔N)) restricts to Lk(TM) and Lk(TN); with [M⊔N]=[M]+[N] by [F4] this gives L[M⊔N]=L[M]+L[N]. For the opposite orientation, T(−M)=TM (the tangent bundle does not see the orientation), while [−M]=−[M] by [F4], so L[−M]=−L[M].

1.2givenF1F3

Boundary vanishing: if M=∂W with W compact oriented and dim⁡M=4k, then, expanding by [F1], L[M]=∑∣J∣=kcJpJ[M]=∑∣J∣=kcJ⋅0=0 because every Pontryagin number of a boundary vanishes by [F3].

1.3givenF2F5F6F7F8F10

Let M4a,N4b be closed oriented with the product orientation, and write πM,πN for the projections. The tangent splitting [F5] and naturality and multiplicativity [F2] give L(T(M×N))=πM∗L(TM)πN∗L(TN). Its degree-4(a+b) part is ∑i+j=a+bLi(TM)×Lj(TN). By [F10] only i=a,j=b can survive. Evaluating this term on [M]×[N] using [F6] and the matching-degree identity [F7] gives L[M×N]=L[M]L[N]. This uses the class identity from [F8], without its separate monomial-number expansion.

1.4givenF1F2F5F6F7F10algebra

Multiplicativity with the zero convention: if 4∤(m+n), the product and at least one factor have value zero by [F1]. Otherwise suppose m=dim⁡M is not divisible by four, write m=4p+r with 1≤r≤3, and let N have dimension n=4k−m so that M×N has dimension 4k. Then L[M]=0 by [F1]. In the degree-4k part of L(TM)L(TN) only the terms Li(TM)Lj(TN) with i+j=k occur, and Li(TM)∈H4i(M;Q)=0 whenever 4i>m, so i≤p; similarly Lj(TN)=0 whenever 4j>n=4(k−p)−r, so j≤k−p−1 because r≥1; thus i+j≤k−1<k and no term of total degree 4k survives. Hence L[M×N]=0=L[M]L[N], and the same argument with the roles of M and N interchanged covers 4∤dim⁡N.

2.1step 1.1step 1.2F1F2F9

Descent: the value L[M] is additive under disjoint union and vanishes on oriented boundaries by steps 1.1 and 1.2, so it is constant on oriented cobordism classes: for a cobordism V from M0 to M1 with ∂V=−M0⊔M1 by [F9], step 1.2 gives 0=L[∂V]=L[−M0⊔M1]=−L[M0]+L[M1] by step 1.1. Hence L induces a well-defined additive map ΩnSO→Q for each n and, extended Q-linearly, a functional on Ω∗SO⊗Q that assigns the value 0 in degrees not divisible by four. It is unital: L[pt]=1 because the tangent bundle of a point is trivial and L of a trivial bundle is 1 by [F2].

3.1step 1.3step 1.4step 2.1F9∎

By step 2.1 the functional is defined and additive on the rationalized oriented bordism groups, and by steps 1.3 and 1.4 it is multiplicative on products of closed oriented manifolds, with unit value 1; since products of such classes generate Ω∗SO⊗Q biadditively, this makes L a unital Q-algebra homomorphism Ω∗SO⊗Q→Q, assigning each closed oriented 4k-manifold its L-genus and the value 0 in dimensions not divisible by four. The empty disjoint union and the zero class satisfy both sides trivially.

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