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Every LCA group has an open compactly generated subgroup with no open subgroup of infinite index

Statement

Assume the Axiom of Choice (The Axiom of Choice) and Dependent Choice (The axiom of dependent choice: a relation in which every element is related to something admits an N-indexed chain). Let G be a locally compact Hausdorff abelian topological group (Locally compact topological space: every point has a compact neighbourhood; and what this says in a metric space, Hausdorff space: distinct points have disjoint open neighbourhoods; every metrizable space is Hausdorff and the indiscrete topology on two points is not, Topological group: multiplication and inversion are continuous). Then G contains an open (hence closed) subgroup H which is compactly generated and contains no open subgroup of infinite index. For instance, if G is discrete one may take H={0}.

Facts & Assumptions

Given: A locally compact Hausdorff abelian group G, and the Axiom of Choice together with Dependent Choice.

[F1]

Classification of compactly generated abelian groups. Every compactly generated locally compact Hausdorff abelian group is isomorphic as a topological group to Rm×Zn×K for some m,n≥0 and some compact group K. This is Hewitt-Ross, Abstract Harmonic Analysis I, Theorem 9.8, quoted and attributed in the Ross article recorded in the sources (Theorem 3 proof, p. 3); the primary volume is not available here, so the classification is used as a cited theorem and no minimality claim about its axiom basis is made beyond the declared AC and DC.

[F2]

An open subgroup is closed because its complement is a union of open cosets; a closed subgroup of an LCA group is LCA by A locally compact subgroup of a Hausdorff topological group is closed. A compactly generated group is one that contains a compact set generating it as a group; the subgroup ⟨C⟩ generated by a symmetric set C containing the identity is the union of the sets Ck of sums of k elements of C, and it is open as soon as C is a neighbourhood of the identity. A locally compact space has compact neighbourhoods, and sums and finite products of compact sets are compact (A product of finitely many compact spaces is compact in the product topology, A continuous image of a compact space is compact; a continuous real-valued map on a nonempty compact space attains a maximum and a minimum; and a continuous bijection from a compact space to a Hausdorff space is a homeomorphism); closed Euclidean balls are compact (Heine-Borel in Rn: with the Euclidean metric a subset of Rn is compact if and only if it is closed and bounded, and the proof by bisection uses no choice principle; the same holds on the real line). (The subgroup ⟨S⟩ generated by a subset, the cyclic subgroup ⟨g⟩, and cyclic groups, Open cover, subcover, and compact topological space; a compact subset is a subspace that is compact in its own right, Neighbourhood of a point and neighbourhood base, with this library's convention that a neighbourhood need not be open, Locally compact topological space: every point has a compact neighbourhood; and what this says in a metric space, In a locally compact Hausdorff space every open set containing a point contains an open set containing it whose closure is compact and still inside; such a space is regular)

Proof

1.1F2

Choose a compact symmetric neighbourhood C of the identity e of G and put H0:=⟨C⟩=⋃k≥1Ck. Then H0 is an open subgroup of G and is generated by the compact set C, so H0 is compactly generated.

2.1F1F3step 1.1

By [F1] there are m,n≥0, a compact group K and a topological isomorphism φ:H0→Rm×Zn×K. Let H:=φ−1(Rm×{0}×K). Since {0} is open in the discrete group Zn, the set Rm×{0}×K is open in Rm×Zn×K, so H is an open subgroup of H0 and hence open in G; it is closed as well, because its complement in G is the union of the remaining cosets of H, each of which is open by [F3].

3.1F2step 2.1

H is compactly generated. Indeed H is isomorphic under φ to Rm×{0}×K, which is homeomorphic to Rm×K; a closed ball of large radius in Rm is compact and generates Rm as a group, because every v∈Rm is an integer multiple of a vector of sufficiently small norm, and K generates itself, so the compact product of that ball with K generates Rm×K.

4.1F3F4step 2.1step 3.1

Let L≤H be an open subgroup of H. Then H/L is discrete, because every coset of the open subgroup L is open. The composite Rm→H→H/L of the inclusion of the connected factor (under the identification of step 2.1) with the quotient map is continuous, so its image is connected in the discrete space H/L, hence a single point; therefore Rm⊆L. It follows that every coset of L meets {0}×K, so the quotient map restricts to a continuous surjection K→H/L, and H/L is compact as a continuous image of the compact group K; being compact and discrete it is finite. Hence every open subgroup L of H has finite index in H.

5.1step 1.1step 2.1step 3.1step 4.1∎

The subgroup H of steps 1.1-4.1 is open in G, compactly generated, and contains no open subgroup of infinite index. If G is discrete, then H={0} is open, compactly generated as the subgroup generated by the compact set {0}, and its only subgroup is itself, of index 1.

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