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The Leray–Hirsch associated-graded isomorphism lifts without extension ambiguity
Statement
Assume AC. For filter the source by base degree and the target by the cohomological Serre filtration. If the induced map is an isomorphism, then itself is an isomorphism. This conclusion does not choose a splitting of either filtration.
Facts & Assumptions
Given: A Serre fibration over a CW base, a supplied finite homogeneous family , and the displayed actual cup-product map.
Cohomological Serre spectral sequence gives in each total degree the exhaustive, complete Serre filtration and identifies its associated graded with , under AC.
Multiplicative cohomological Serre spectral sequence states that pullback and cup product preserve the filtration and induce the corresponding products on every page.
Finite and complete filtered isomorphism lifting states that a filtered map between the applicable finite complete filtrations is an isomorphism if its associated-graded map is one.
The Axiom of Choice is used only through [F1]–[F2].
Proof
Put a summand in filtration at least when its base class has Serre filtration at least . By [F2], has that filtration and cupping with the fixed class cannot decrease it. Hence the displayed is a filtered homomorphism, not merely a map invented on .
Fix total degree . The first-quadrant bounds make both induced filtrations finite in that degree, while [F1] supplies exhaustivity, completeness, and the identification with the stable page. Under the hypothesis that is an isomorphism, [F3] therefore says is an isomorphism.
Applying step 2.1 in every degree proves the graded-module assertion. The inverse is obtained by the filtered-isomorphism lemma from kernels and cokernels along the finite filtration; no complements or splitting maps are chosen. Empty summand families and the zero ring give zero maps between zero modules, a one-step filtration reduces to the assumed graded isomorphism, and filtration endpoints are covered by finiteness. AC is used exactly through [A1] in the cohomological Serre suppliers.
Depends on
Used by
- Leray–Hirsch module isomorphism Theorem
Dependency tree · two levels
38 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Miller, MIT 18.906 notes, proof of Theorem 33.5 (standard reference, not scraped)