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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-09-14
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The Leray–Hirsch associated-graded isomorphism lifts without extension ambiguity

Statement

Assume AC. For Φ((ai))=ipaiei, filter the source by base degree and the target by the cohomological Serre filtration. If the induced map grΦ is an isomorphism, then Φ itself is an isomorphism. This conclusion does not choose a splitting of either filtration.

Facts & Assumptions

Given: A Serre fibration over a CW base, a supplied finite homogeneous family (ei), and the displayed actual cup-product map.

[F1]

Cohomological Serre spectral sequence gives in each total degree the exhaustive, complete Serre filtration and identifies its associated graded with E, under AC.

[F2]

Multiplicative cohomological Serre spectral sequence states that pullback and cup product preserve the filtration and induce the corresponding products on every page.

[F3]

Finite and complete filtered isomorphism lifting states that a filtered map between the applicable finite complete filtrations is an isomorphism if its associated-graded map is one.

[A1]

The Axiom of Choice is used only through [F1]–[F2].

Proof

technique · lift the actual filtered map
1.1

Put a summand Hqei(B;R) in filtration at least p when its base class has Serre filtration at least p. By [F2], pai has that filtration and cupping with the fixed class ei cannot decrease it. Hence the displayed Φ is a filtered homomorphism, not merely a map invented on E.

F2
2.1

Fix total degree q. The first-quadrant bounds make both induced filtrations finite in that degree, while [F1] supplies exhaustivity, completeness, and the identification with the stable page. Under the hypothesis that grΦ is an isomorphism, [F3] therefore says Φ:HsourceqHq(E;R) is an isomorphism.

F1F3step 1.1
3.1

Applying step 2.1 in every degree proves the graded-module assertion. The inverse is obtained by the filtered-isomorphism lemma from kernels and cokernels along the finite filtration; no complements or splitting maps are chosen. Empty summand families and the zero ring give zero maps between zero modules, a one-step filtration reduces to the assumed graded isomorphism, and filtration endpoints are covered by finiteness. AC is used exactly through [A1] in the cohomological Serre suppliers.

F1F3A1step 2.1

Depends on

Used by

Dependency tree · two levels

38 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources