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Leray–Hirsch module isomorphism
Statement
Assume AC, and let be a commutative unital ring. Let be a Serre fibration over a path-connected CW complex, and suppose the finitely many homogeneous classes restrict to an -basis on every fiber. Then is an -module isomorphism. It is natural for maps of such fibrations that pull the specified classes on the target to the specified classes on the source.
Facts & Assumptions
Given: The commutative unital ring, fibration, finite homogeneous family, and basis hypothesis in the statement.
A global fiber basis trivializes Serre monodromy identifies the fiber-cohomology system as constant in the displayed basis.
The Leray–Hirsch associated-graded isomorphism lifts without extension ambiguity lifts the associated-graded basis isomorphism for this actual map .
Cohomological Serre spectral sequence identifies the page and the edge classes, while Multiplicative cohomological Serre spectral sequence identifies cup products and their pagewise products.
The Axiom of Choice is assumed exactly as in [F1]–[F2].
Proof
By [F1] and [F3], the page is in the named basis. Each comes from total-space cohomology, so its fiber restriction is represented by the fiber edge and is a permanent cycle. The product in [F3] therefore makes the map induced by on the basis map . It is an isomorphism in every bidegree.
A morphism of spectral sequences that is an isomorphism on one page is an isomorphism on all subsequent pages, so step 1.1 gives the associated-graded isomorphism at . Applying [F2] to the actual filtered cup-product map proves that is an isomorphism in every total degree.
The formula gives , so it is an -module map. For a map of fibrations carrying every specified target to the corresponding source , contravariance of pullback and cup naturality make the two displayed formulas commute; this is the asserted, choice-of-basis-relative naturality. If the finite list is empty, all fiber cohomology is zero and both sides are zero; one basis element, the zero ring, degree-zero classes, and filtration endpoints are included in steps 1.1–2.1. No splitting or basis is selected, and AC is used exactly through [A1].
Depends on
Used by
Dependency tree · two levels
41 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Miller, MIT 18.906 notes, Theorem 33.5 (standard reference, not scraped)
- Hatcher, Vector Bundles and K-Theory (standard reference, not scraped)