LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31‡ rests on unproved material (inherited)

How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

‡ Rests on 3 statements not proved in this library, by way of the results it cites. This item cites no such statement directly; it depends on results that do. The unproved premises it inherits are ‡ Cohen's first model: an infinite Dedekind-finite set of reals, ‡ Sierpiński 1947: the generalised continuum hypothesis implies the Axiom of Choice and ‡ The continuum hypothesis and its generalisation are independent of ZFC. Each is recorded with a citation to the literature and is not established here, because the track that would prove it has not yet been developed in this library. Everything else in this proof is proved here.

Under choice, $L(X)$ is a well-defined cardinal

Statement

Assuming choice, $L(X)$ is a well-defined cardinal.

Facts & Assumptions

Given: A topological space $X$ and the definition in Under choice, Lindelöf degree $L(X)$ and cellularity $c(X)$ as raw cardinal functions.

[A1]

Under choice every set has a cardinality (Cardinal (initial ordinal) and cardinality, The well-ordering theorem).

[L1]

Every nonempty set of ordinals, and hence every nonempty set of cardinals, has a least member; this is a theorem of ZF (Trichotomy and well-ordering of the ordinals).

Proof

technique · direct

1.1

By [A1], the topology $\tau$ has a cardinality $\kappa$ . Every open cover is a subcover of itself and has cardinality at most $\kappa$ , so $\kappa$ bounds every cover's subcover size.

A1given

2.1

Let $S$ be the set of cardinals $\lambda\leq\kappa$ such that every open cover of $X$ has a subcover of cardinality at most $\lambda$ . By Step 1.1, $\kappa\in S$ , so [L1] supplies a least member of $S$ . Any bounding cardinal larger than $\kappa$ cannot be smaller than that member, and hence this least member is exactly $L(X)$ .

step 1.1L1∎

Depends on

Used by

Cited to discharge well-definedness by Under choice, Lindelöf degree L(X) and cellularity c(X) as raw cardinal functions.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 55 results over 18 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources

D. H. Fremlin, Measure Theory, Chapter 5A (standard reference, not scraped)

Under choice, L(X)L(X)L(X) is a well-defined cardinal