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Trace control of the regularized design determinant

Statement

Let d,n≥1, let λ>0, let L≥0, and let a1,…,an∈Rd satisfy ∥at∥2≤L. Put Vt=λId+∑s=1tasasT and V0=λId, and define tr⁡(M)=∑i=1dMii. Then

0<det⁡Vt(0≤t≤n),log⁡ ⁣(det⁡Vndet⁡V0)≤dlog⁡ ⁣(1+nL2dλ).

Facts & Assumptions

Given: Positive integers d,n, reals λ>0 and L≥0, and vectors at∈Rd with ∥at∥2≤L.

[F1]

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: ∥x∥22=xTx and the standard inner product is positive definite.

[F4]

The arithmetic mean, geometric mean inequality: for positive reals μ1,…,μd, ∏iμi≤(1d∑iμi)d.

[F5]

Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: the natural logarithm is strictly increasing on positive reals and log⁡(xd)=dlog⁡x for x>0.

Proof

1.1givenF1F2algebrachoose

For every nonzero x∈Rd, xTVnx=λ∥x∥22+∑t=1n(atTx)2>0. Thus Vn is symmetric positive definite. By [F2], choose an orthogonal matrix Q and positive eigenvalues μ1,…,μd with Vn=Qdiag⁡(μ1,…,μd)QT.

1.2givenF1F2F3algebra

For each 0≤t≤n, xTVtx=λ∥x∥22+∑s=1t(asTx)2>0 for every nonzero x. Thus Vt is symmetric positive definite. By [F2], write Vt=Qtdiag⁡(ν1,…,νd)QtT with Qt orthogonal; positive definiteness gives νi>0 for each i. By [F3], det⁡(QtT)=det⁡(Qt) and det⁡(diag⁡(ν1,…,νd))=∏iνi. Since QtTQt=Id, multiplicativity gives det⁡(Qt)2=1, hence det⁡Vt=∏iνi>0.

2.1step 1.1F3algebra

Since QTQ=Id, [F3] gives (det⁡Q)2=1. Applying [F3] to the diagonalization yields det⁡Vn=(det⁡Q)(∏iμi)(det⁡QT)=∏iμi>0. Also, expanding the diagonal entries of Qdiag⁡(μi)QT gives tr⁡(Vn)=∑j=1dμj∑i=1dQij2=∑j=1dμj, because each column of Q has Euclidean norm one.

3.1givenstep 2.1F1F4algebra

By [F4] and step 2.1, det⁡Vn=∏iμi≤(∑iμid)d=(tr⁡(Vn)d)d. The definition of Vn gives tr⁡(Vn)=dλ+∑t∥at∥22≤dλ+nL2.

4.1givenF3step 3.1algebra

Since V0=λId is diagonal, [F3] gives det⁡V0=λd>0. Dividing step 3.1 by this positive number yields det⁡Vndet⁡V0≤(1+nL2dλ)d.

5.1step 2.1step 4.1step 1.2F5algebra∎

The two sides in step 4.1 are positive by steps 2.1 and 4.1. Applying the increasing natural logarithm and then [F5] gives the claimed bound.

Depends on

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