How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Localized cone triangles satisfy tr one through tr three
Statement
In let distinguished triangles mean triangles isomorphic to images of cone triangles in . The cochain shift descends and these triangles satisfy TR1, signed TR2, and TR3.
Facts & Assumptions
Given: In let distinguished triangles mean triangles isomorphic to images of cone triangles in . The cochain shift descends and these triangles satisfy TR1, signed TR2, and TR3.
The derived category is localization at quasi-isomorphisms (Derived category of an abelian category).
The roof localization is additive and preserves zero and biproducts (Addition of roofs makes an additive localization).
A commuting localized square on two ordinary arrows clears to two ordinary commuting squares with denominator comparisons (Finite roof squares and composable pairs can be cleared).
The homotopy category of an abelian category is triangulated (The homotopy category of an abelian category is triangulated).
Homology on the homotopy category is homological (Homology is a homological functor on the homotopy category).
In a map of exact five-term sequences, isomorphisms in positions one, two, four and five imply an isomorphism in position three (Five lemma in an abelian category).
Proof
The additive localization exists. Since a quasi-isomorphism remains one after either shift, shifting both arrows of a roof defines mutually inverse additive shifts. The zero complex and identity triangles descend as well.
For any arrow write with a quasi-isomorphism. A cone triangle on descends and transport along completes . Closure under isomorphism is built into the definition. Rotation gives because this is the rotation in ; shifting a roof preserves the minus sign. This proves TR1 and both directions of TR2.
For TR3 first replace the two triangles by images of triangles on ordinary maps . Apply the square-clearing lemma to the prescribed first two components. It supplies a third ordinary arrow and two commuting squares with maps and denominator maps into . Complete each square to a morphism of cone triangles in by its TR3, giving third maps and .
For every , take the five consecutive terms , , , , and their counterparts for . Exactness holds in ; four vertical maps are isomorphisms because are quasi-isomorphisms. The five lemma makes an isomorphism. Hence is a quasi-isomorphism before any triangulation of is used.
Put the third localized component equal to . The two morphisms of triangles in , with the now invertible comparison , give all three commuting triangle squares and the shifted first component. Transporting back proves TR3 for the original data.
Depends on
Used by
Dependency tree · two levels
25 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- 13.5.5–13.5.6, including all TR1–TR4 proof paragraphs (standard reference, not scraped)