Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A locally finite family of continuous nonnegative functions has a continuous pointwise sum

Statement

Let {fs:X[0,)}sS\{f_s:X\to[0,\infty)\}_{s\in S} be continuous and suppose that {coz(fs)}sS\{\operatorname{coz}(f_s)\}_{s\in S} is locally finite. Then f(x):=sSfs(x)f(x):=\sum_{s\in S}f_s(x) is a well-defined continuous map X[0,)X\to[0,\infty).

Facts & Assumptions

Given: A locally finite family of cozero sets of continuous nonnegative functions on XX.

[F1]

At every point, a locally finite family has a neighbourhood meeting only finitely many members (Locally finite partitions of unity and subordination to an open cover).

Proof

technique · direct
1.1

Fix xXx\in X and a neighbourhood NN meeting only coz(fs1),,coz(fsn)\operatorname{coz}(f_{s_1}),\ldots,\operatorname{coz}(f_{s_n}); every fsf_s with s{s1,,sn}s\notin\{s_1,\ldots,s_n\} vanishes on NN.

F1
2.1

Thus at every point of NN the displayed pointwise sum equals the finite sum fs1++fsnf_{s_1}+\cdots+f_{s_n}, so it is well defined and agrees on NN with a continuous function.

step 1.1L1
3.1

Since every point has such a neighbourhood NN, the pointwise sum is continuous on XX and is nonnegative.

step 2.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 45 results over 12 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources