How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Many good -vertex subsets force many homogeneous -sets
Statement
Let be integers, and let be a class of finite graphs such that every graph in has the -homogeneous property. Let be a finite graph on vertices. Suppose at least half of the sets contain a -element subset with . Then has at least
homogeneous vertex sets of size .
Facts & Assumptions
Given: Positive integers , a class of finite graphs, integers , an -vertex graph , and the hypothesis that at least half of the sets contain a -element subset with .
If a graph lies in , then every -element subset of its vertex set contains a homogeneous -element subset (The -homogeneous property, Homogeneous vertex sets and the homogeneous number ).
For a subset , the induced subgraph on is (Subgraphs, induced subgraphs and spanning subgraphs).
counts the -element subsets of an -element set (The set of -element subsets and the binomial coefficient ).
A finite relation can be counted by summing its row fibres or its column fibres (Double counting: for a relation between finite sets).
Proof
Call a set good when it contains a -element subset with ; by hypothesis, there are at least good sets.
If is good, choose with and ; then [L1] gives a homogeneous -element subset , and since is the induced subgraph on , that same set is homogeneous in .
Let be the relation between the homogeneous -element subsets of and the good sets defined by . Step 1.2 shows that every good is related to at least one , so [L4] gives .
For the relation of step 2.1, fix a homogeneous -element subset of . The good sets with are among the -element supersets of , and [L3] counts those as . If is the number of homogeneous -element subsets of , then [L4] gives .
Comparing steps 2.1 and 3.1 yields .
Since , each factor in the ratio formula satisfies for , so . Therefore .
Depends on
- The $(t,k)$-homogeneous property
- Subgraphs, induced subgraphs and spanning subgraphs
- Homogeneous vertex sets and the homogeneous number $\operatorname{hom}(G)=\max\{\omega(G),\alpha(G)\}$
- The set $[A]^{k}$ of $k$-element subsets and the binomial coefficient $\binom{n}{k} := \lvert [n]^{k}\rvert$
- Double counting: $\sum_{x \in X}\lvert R_x\rvert = \lvert R\rvert = \sum_{y \in Y}\lvert R^y\rvert$ for a relation between finite sets
Used by
Dependency tree · two levels
19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- M. Bucić, J. Fox, and H. T. Pham, Equivalence between Erdős-Hajnal and polynomial Rödl and Nikiforov conjectures, Lemma 13 (standard reference, not scraped)
- T. H. Nguyen, Notes on Recent Work on the Erdős–Hajnal Conjecture, Lemma 13 (standard reference, not scraped)