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Without a large -sparse induced subgraph, the number of -vertex stable sets is bounded
Statement
Let , let be integers, and let be positive integers with
Let be a finite graph on vertices such that every subset with induces a graph of maximum degree at least . Then has at most
stable sets of size .
In particular, the same bound holds whenever has no -sparse induced subgraph on or more vertices.
Facts & Assumptions
Given: A real , integers , positive integers with , and an -vertex graph satisfying the maximum-degree hypothesis in the Statement.
Stable sets are vertex sets with no adjacent pair (Cliques, stable sets, the clique number and stability number ).
Binomial coefficients count subsets, and Pascal's rule is (The set of -element subsets and the binomial coefficient , Pascal's rule , and the hockey-stick identity ).
If a vertex set induces a graph whose maximum degree is less than , then is -sparse; equivalently, the failure of -sparsity forces some vertex degree to exceed (-sparse, -dense and -restricted vertex sets, A set is -sparse exactly when the maximum degree of the graph it induces is at most times its size).
Proof
[base] If , then the hypothesis reads . Every stable -set is a -element subset of the -vertex set, so there are at most of them by [L2].
[ih] Assume and that the claim holds for every admissible parameter tuple with smaller value of .
If , then every stable -set is a -element subset of the -vertex set, so there are at most of them by [L2]. Thus the claim is immediate in this case. We may therefore assume . Take of maximum degree. Applying the hypothesis to gives . Let , so .
Stable -sets containing correspond exactly to stable -sets of . Since , the induction hypothesis applied to with parameters shows that there are at most such stable sets.
Stable -sets avoiding are stable -sets of . Any subset of with at least vertices is also a subset of , so it still satisfies the maximum-degree hypothesis. The induction hypothesis applied to with parameters therefore bounds their number by .
Adding the bounds from steps 2.1 and 2.2 and using Pascal's rule from [L2] gives at most stable -sets in , in the sense of [L1]. If has no -sparse induced subgraph on or more vertices, then [L3] shows that every such induced subgraph has a vertex of degree exceeding , hence in particular at least , so the same bound applies in that situation as well.
Depends on
- $c$-sparse, $c$-dense and $c$-restricted vertex sets
- A set is $c$-sparse exactly when the maximum degree of the graph it induces is at most $c$ times its size
- Cliques, stable sets, the clique number $\omega(G)$ and stability number $\alpha(G)$
- The set $[A]^{k}$ of $k$-element subsets and the binomial coefficient $\binom{n}{k} := \lvert [n]^{k}\rvert$
- Pascal's rule $\binom{n+1}{k+1} = \binom{n}{k} + \binom{n}{k+1}$, and the hockey-stick identity $\sum_{i \le n}\binom{i}{k} = \binom{n+1}{k+1}$
Used by
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Sources
- M. Bucić, J. Fox, and H. T. Pham, Equivalence between Erdős-Hajnal and polynomial Rödl and Nikiforov conjectures, Lemma 12 (standard reference, not scraped)
- T. H. Nguyen, Notes on Recent Work on the Erdős–Hajnal Conjecture, Lemma 1.5 (standard reference, not scraped)