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Without a large ϵ-sparse induced subgraph, the number of k-vertex stable sets is bounded

Statement

Let ϵ(0,1], let 0k be integers, and let u,n be positive integers with

(1ϵ)nu.

Let G be a finite graph on n vertices such that every subset SV(G) with Su induces a graph G[S] of maximum degree at least ϵS1. Then G has at most

(n)(uk)

stable sets of size k.

In particular, the same bound holds whenever G has no ϵ-sparse induced subgraph on u or more vertices.

Facts & Assumptions

Given: A real ϵ(0,1], integers 0k, positive integers u,n with (1ϵ)nu, and an n-vertex graph G satisfying the maximum-degree hypothesis in the Statement.

[L1]
[L3]

If a vertex set S induces a graph whose maximum degree is less than ϵS, then S is ϵ-sparse; equivalently, the failure of ϵ-sparsity forces some vertex degree to exceed ϵS (c-sparse, c-dense and c-restricted vertex sets, A set is c-sparse exactly when the maximum degree of the graph it induces is at most c times its size).

Proof

technique · induction
1.1

[base] If =0, then the hypothesis (1ϵ)nu reads nu. Every stable k-set is a k-element subset of the n-vertex set, so there are at most (nk)(uk)=(n0)(uk) of them by [L2].

L2
1.2

[ih] Assume 1 and that the claim holds for every admissible parameter tuple with smaller value of +n.

base
1.3

If un, then every stable k-set is a k-element subset of the n-vertex set, so there are at most (nk)(n)(nk)(n)(uk) of them by [L2]. Thus the claim is immediate in this case. We may therefore assume u<n. Take vV(G) of maximum degree. Applying the hypothesis to S=V(G) gives degG(v)ϵn1. Let U:=V(G)({v}NG(v)), so U(1ϵ)n.

L2givenchoosealgebra
2.1

Stable k-sets containing v correspond exactly to stable (k1)-sets of G[U]. Since (1ϵ)1U(1ϵ)nu, the induction hypothesis applied to G[U] with parameters (1,k1) shows that there are at most (U1)(uk)(n11)(uk) such stable sets.

step 1.2step 1.3L2
2.2

Stable k-sets avoiding v are stable k-sets of Gv. Any subset of V(Gv) with at least u vertices is also a subset of V(G), so it still satisfies the maximum-degree hypothesis. The induction hypothesis applied to Gv with parameters (,k) therefore bounds their number by (n1)(uk).

step 1.2step 1.3
3.1

Adding the bounds from steps 2.1 and 2.2 and using Pascal's rule from [L2] gives at most ((n11)+(n1))(uk)=(n)(uk) stable k-sets in G, in the sense of [L1]. If G has no ϵ-sparse induced subgraph on u or more vertices, then [L3] shows that every such induced subgraph has a vertex of degree exceeding ϵS, hence in particular at least ϵS1, so the same bound applies in that situation as well.

step 2.1step 2.2L1L2L3discharge-induction

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Sources