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Perfectness, vanishing correction, and vanishing handle boundaries

Statement

Assume ACω. Let M be a closed smooth n-manifold, let f:M→R be Morse, let F be a field, let Q be the correction polynomial of the Morse polynomial identity and let (C∙,∂∙) be a handle chain complex of (M,f,F). The following are equivalent:

(i) f is F-perfect;

(ii) Q=0;

(iii) every handle boundary map vanishes, ∂k=0 for all k (equivalently dim⁡Fim⁡∂k+1=0 for all k).

Facts & Assumptions

Given: A closed smooth n-manifold M, a Morse function f, a field F, the unique correction polynomial Q(t)=∑kqktk with qk≥0 of the identity Mf=PM,F+(1+t)Q, and a handle chain complex (C∙,∂∙).

[F1]

Mf=PM,F+(1+t)Q with Q∈Z[t] having nonnegative coefficients, and Q is the unique such polynomial (Morse polynomial identity).

[F2]

f is F-perfect exactly when mk(f)=bk(M;F) for all k, equivalently when Mf=PM,F (Perfect Morse function over a field).

[F3]

The handle chain complex has dim⁡FCk=mk(f), it is a chain complex with ∂k−1∂k=0, and Hk(C∙)≅Hk(M;F), so dim⁡FHk(C∙)=bk(M;F); all these spaces are finite-dimensional (The handle chain complex computes singular homology).

[L1]

For a linear map T:V→W with V finite-dimensional, dim⁡FV=dim⁡Fker⁡T+dim⁡Fim⁡T (Rank-nullity: dim⁡FV=nullity⁡T+rank⁡T, Rank and nullity of a linear map with finite-dimensional domain).

[L2]

The rank bookkeeping for a short exact sequence 0→A→B→C→0 of finite-dimensional F-vector spaces gives dim⁡FB=dim⁡FA+dim⁡FC: it is the one-term case of the alternating partial-sum identity with all other terms zero and injective first map (Rank bookkeeping for a long exact sequence of finite-dimensional vector spaces).

Proof

technique · rank-comparison
1.1F1F2given

(i)⇔(ii): if f is F-perfect, then Mf=PM,F by [F2], so (1+t)Q=0 and uniqueness in [F1] gives Q=0 (the zero polynomial is a solution). Conversely, if Q=0, then Mf=PM,F by [F1], and coefficient comparison gives mk(f)=bk(M;F) for every k, which is perfectness by [F2].

1.2F3F2given

(iii)⇒(i): if ∂k=0 for every k, then Hk(C∙)=Ck and hence, by [F3], mk(f)=dim⁡FCk=dim⁡FHk(C∙)=bk(M;F) for every k; by [F2] the function f is F-perfect.

1.3F3L1L2L3given

(i)⇒(iii): for every k, [L1] applied to ∂k:Ck→Ck−1 gives dim⁡FCk=dim⁡Fker⁡∂k+dim⁡Fim⁡∂k, and the same rank-nullity identity applied to the short exact sequence 0→im⁡∂k+1→ker⁡∂k→Hk(C∙)→0 (whose terms are finite-dimensional by [F3] and [L3]) gives, by [L2], dim⁡Fker⁡∂k=dim⁡Fim⁡∂k+1+dim⁡FHk(C∙). Substituting and using [F3] yields mk(f)−bk(M;F)=dim⁡Fim⁡∂k+1+dim⁡Fim⁡∂k ≥0. If f is F-perfect, the left side vanishes for every k; both terms on the right are nonnegative dimensions, so both vanish for every k, that is im⁡∂k+1=0 and im⁡∂k=0 for all k, which is (iii).

2.1step 1.1step 1.2step 1.3∎

Steps 1.1, 1.2 and 1.3 give (i)⇔(ii) and (i)⇔(iii), so all three statements are equivalent. In particular perfectness over F is exactly the vanishing of all handle boundaries over F; over the integers the corresponding boundary maps need not vanish, since a nonzero integral boundary coefficient can vanish after reduction modulo the characteristic of F.

Remarks

  • Measure of the loss. The identity of step 1.3 exhibits the defect mk−bk as the total dimension of the two boundary maps meeting in degree k; this is the handle-side reading of the correction polynomial.
  • No identification with the Morse differential. The vanishing is asserted for the handle boundary maps of the handle chain complex constructed on this page; the trajectory-count definition of the Morse differential and its comparison with these maps belong to the later Morse-homology page and are not used here.

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Sources