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Uniform interval stability of the phase-field L2 projector

Statement

Let Ω=(0,L) and let Vh be the conforming interval space in No-flux finite-volume and conforming realizations for phase fields, with center spacing h. Let Ihv interpolate the absolutely-continuous representative of v∈H1(0,L) at the centers and extend it constantly to the two boundary half-cells. Let Ph be the exact L2-orthogonal projection onto Vh. There is a constant C independent of h such that ∥Ihv∥H1≤C∥v∥H1,∥v−Ihv∥L2≤Ch∥v′∥L2,∥Phv∥H1≤C∥v∥H1. In addition, ∥Phv−v∥L2≤Ch∥v′∥L2 for every v∈H1(0,L), Phv→v in H1(0,L) for every v∈H1(0,L), and Phg→g in L2(0,L) for every g∈L2(0,L) as h→0.

Facts & Assumptions

Given: A bounded interval, a uniform center mesh, and the definitions of Vh, Ih, and Ph in the statement.

[F1]

No-flux finite-volume and conforming realizations for phase fields: Vh consists of continuous functions affine between centers and constant on the boundary half-cells, so its L2 inner product is positive definite and Ph is the orthogonal projection.

[F2]

One-dimensional W1,p functions have unique absolutely continuous representatives: each H1(0,L) class has a unique absolutely-continuous representative on [0,L] with v(x)−v(y)=∫yxv′(s) ds.

[F3]

Assume Countable Choice. For every g∈L2(0,L) and δ>0 there is q∈Cc∞(0,L) with ∥g−q∥2<δ (Smooth compactly supported functions of an open set are dense in L2).

[F4]

Every compactly supported smooth function on (0,L) lies in H1(0,L) because its classical derivatives are weak derivatives (Classical derivatives agree with weak derivatives).

[A1]

Assume the Axiom of Choice through [F2] when selecting the canonical representative at the finitely many interpolation nodes; it supplies the Countable Choice hypothesis in [F3].

Proof

1.1A1F1F2givenalgebra

On every segment between adjacent centers, Ihv has slope h−1∫xixi+1v′(s) ds, so Cauchy–Schwarz bounds its squared derivative integral by ∫xixi+1∣v′∣2. It is constant on the boundary half-cells. Summing proves ∥(Ihv)′∥2≤∥v′∥2. The fundamental-theorem identity in [F2] gives ∣v(x)−Ihv(x)∣≤2h∥v′∥L2(K) on each center interval K and the same bound on each boundary half-cell. Squaring and summing proves ∥v−Ihv∥2≤Ch∥v′∥2; then ∥Ihv∥2≤∥v∥2+Ch∥v′∥2.

1.2F1algebra

For an affine function wh on an interval J of length h with endpoint values a,b, direct integration gives ∥wh′∥L2(J)2=(b−a)2/h and ∥wh∥L2(J)2=h(a2+ab+b2)/3≥h(a2+b2)/6. Hence ∥wh′∥L2(J)≤12h−1∥wh∥L2(J). Summing this inequality over the affine segments proves the inverse estimate ∥wh′∥2≤12h−1∥wh∥2 on Vh; the constant boundary segments add no derivative.

2.1F1step 1.1step 1.2algebra

Since PhIhv=Ihv and Ph is an L2 contraction, ∥Phv−Ihv∥2=∥Ph(v−Ihv)∥2≤Ch∥v′∥2 by step 1.1. The triangle inequality with step 1.1 gives ∥Phv−v∥2≤Ch∥v′∥2. Apply step 1.2 to Phv−Ihv∈Vh, and then step 1.1, to obtain ∥(Phv)′∥2≤∥(Ihv)′∥2+Ch−1∥Phv−Ihv∥2≤C∥v′∥2. The L2 contraction gives the full H1 stability.

3.1step 2.1givenalgebra

If v∈C2([0,L]), linear interpolation on each interior segment has H1 error tending to zero, while on a boundary half-cell the derivative error is bounded by h∥v′∥∞. Thus ∥Ihv−v∥H1→0. Step 2.1 applied to v−Ihv gives ∥Phv−Ihv∥H1≤C∥v−Ihv∥H1→0, so Phv→v in H1.

4.1A1F2F3step 2.1step 3.1givenalgebra

For arbitrary v∈H1(0,L), let v′ be its L2 weak derivative and use [F3] to choose qj∈Cc∞(0,L) with qj→v′ in L2. Define vj(x)=v(0)+∫0xqj(s) ds using the representative in [F2]. Then vj∈C∞([0,L]) and ∥vj′−v′∥2=∥qj−v′∥2→0, while Cauchy--Schwarz gives ∥vj−v∥2≤L∥qj−v′∥2. Hence vj→v in H1. Uniform stability from step 2.1 and smooth convergence from step 3.1 yield ∥Phv−v∥H1≤C∥v−vj∥H1+∥Phvj−vj∥H1+∥vj−v∥H1; first let h→0 with j fixed and then let j→∞. Thus Phv→v in H1 for every v∈H1(0,L).

5.1A1F1F3F4step 2.1givenalgebra∎

For g∈L2(0,L) and δ>0, [F3] gives q∈Cc∞(0,L)⊂H1(0,L) with ∥g−q∥2<δ. The orthogonal projector is an L2 contraction by [F1], and step 2.1 gives Phq→q in L2. Therefore ∥Phg−g∥2≤2∥g−q∥2+∥Phq−q∥2, so lim sup⁡h→0∥Phg−g∥2≤2δ. Letting δ↓0 proves strong L2 convergence for every g∈L2(0,L).

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