Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passverified 2026-08-09 (gpt-5.6-terra-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The minimal Cauchy filters associated to points define a uniformly continuous dense canonical map

Statement

The map η:X→X^ sending x to the minimal Cauchy filter associated to its principal filter is uniformly continuous and has dense image. For every x∈X, every member of η(x) contains x.

Facts & Assumptions

Given: A uniform space X and its minimal-Cauchy-filter space X^.

[L1]

Principal filters are Cauchy and have associated minimal Cauchy filters (Every Cauchy filter canonically determines a unique minimal Cauchy filter coarser than it).

[L2]
[L4]

Symmetric entourages with prescribed finite-composite control may be chosen inside any entourage (Every uniformity has a base of symmetric entourages).

Proof

technique · constructive
1.1

Define η(x) to be the minimal filter associated to the principal filter Px at x. Since η(x)=m(Px)⊆Px, every member of η(x) contains x.

L1construct
1.2

Let E^[F] be a basic neighbourhood. Choose a symmetric D with D∘2⊆E, a D-small A∈F, and a∈A. The point filter η(a) contains D[a], and D[a]×A⊆D∘2⊆E, so η(a)∈E^[F]. Thus every basic neighbourhood meets η[X].

L1L2L3L4choose
2.1

Given a target basic entourage E^, choose a symmetric D with D∘3⊆E. If (x,y)∈D, then D[x]∈η(x) and D[y]∈η(y), while D[x]×D[y]⊆D∘3⊆E. Hence (η(x),η(y))∈E^, which proves uniform continuity.

step 1.1L2L4
3.1

Thus every neighbourhood meets η[X], so its closure is all of X^ and the image is dense.

step 1.2L3discharge-construct∎

Depends on

Used by

Dependency tree · two levels

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Sources