Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A proper geometrically integral affine scheme is a point

Statement

Assume the Axiom of Choice. A proper geometrically integral affine finite-type k-scheme is Spec⁡k. Every morphism from a proper geometrically integral finite-type k-scheme to an affine k-scheme factors through a k-rational point. In particular a positive-dimensional abelian variety is not affine.

Facts & Assumptions

[F1]

Under AC, Γ(X,OX)=k for proper geometrically integral X. (Global functions on proper integral schemes form a finite extension of the base field)

[F2]

Global sections recover the ring of an affine scheme, and morphisms into an affine scheme correspond to ring maps on global sections. (Global functions on Spec A recover A, Morphisms to an affine scheme and global sections)

[F3]

An abelian variety is proper and geometrically integral. (Abelian varieties over a field)

Proof

Given: AC and X proper geometrically integral of finite type over k.

1.1F1F2given

If X=Spec⁡B is affine, [F1] and [F2] identify B with k as a k-algebra. Taking spectra gives X≅Spec⁡k.

2.1F1F2F3step 1.1∎

For an arbitrary affine target T=Spec⁡B, a k-morphism X→T corresponds by [F2] to a k-algebra map B→Γ(X,OX)=k. That map defines a k-rational point of T, and naturality in [F2] gives the desired factorization through X→Spec⁡k. By [F3], an affine abelian variety would be a point by step 1.1, so a positive-dimensional abelian variety cannot be affine. AC is used precisely through [F1].

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Sources