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Orthogonal error restrictions determine syndrome projections

Statement

Let HL,HO be finite-dimensional complex inner-product spaces, and let Wi:HL→HO be finitely many isometries with pairwise orthogonal ranges. Then Pi=WiWi∗ are pairwise orthogonal projections, their sum S=∑iPi is an orthogonal projection satisfying 0≤S≤IHO, and Q=IHO−S is the orthogonal projection onto the residual complement. The empty family is allowed, with S=0 and Q=IHO.

Facts & Assumptions

Given: Finite-dimensional complex inner-product spaces HL,HO and a finite family of isometries Wi:HL→HO with pairwise orthogonal ranges.

[F2]

An endomorphism is an orthogonal projection exactly when it is idempotent and self-adjoint: a self-adjoint idempotent on a finite-dimensional inner-product space is an orthogonal projection.

[F3]

The orthogonal projection PWv is the W-component in V=W⊕W⊥: an orthogonal projection selects the component in its range along the orthogonal complement.

[F4]
[F5]

Non-negative and positive operators: 0≤T means T is self-adjoint and ⟨Tx,x⟩≥0 for every x.

[F6]

Real and complex inner product spaces, with the inner product linear in the first argument: ⟨x,x⟩=∥x∥2 and the inner product is positive definite.

[F7]

An isometric quantum encoding gives an orthogonal code projector: every finite-dimensional linear isometry W satisfies W∗W=I.

Proof

1.1givenF2F4F7F8algebra

By [F7, F8], each Wi has an adjoint and Wi∗Wi=I. For each i, [F4] gives Pi∗=(WiWi∗)∗=WiWi∗, and Pi2=Wi(Wi∗Wi)Wi∗=WiWi∗=Pi by [F7]. The image of Pi is contained in ran⁡Wi, while PiWix=Wix for every x; hence its image equals ran⁡Wi. By [F2], Pi is the orthogonal projection onto that range.

2.1givenstep 1.1F2F4F6F8algebra

If i≠j, orthogonality of the ranges gives ⟨x,Wi∗Wjy⟩=⟨Wix,Wjy⟩=0 for all x,y∈HL by [F8]. Taking x=Wi∗Wjy shows Wi∗Wj=0 by [F6]. Hence PiPj=Wi(Wi∗Wj)Wj∗=0. Thus S∗=S and S2=∑iPi2+∑i≠jPiPj=S; [F2] makes S an orthogonal projection. The same calculation gives (I−S)∗=I−S=(I−S)2, so [F2] makes Q=I−S an orthogonal projection.

3.1step 1.1step 2.1F2F3F5F6algebra∎

Each Pi fixes its own range and kills the other ranges, so ran⁡S is exactly the orthogonal sum of the ran⁡Wi. Since Q=I−S is an orthogonal projection, its range is ker⁡S, the orthogonal complement of the range of S by [F3]. For every x∈HO, ⟨Sx,x⟩=∥Sx∥2≥0 and ⟨Qx,x⟩=∥Qx∥2≥0, so [F5] gives 0≤S≤I. For the empty family the sums give S=0,Q=I directly.

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Sources