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The projective one-qubit group is SO(3)

Statement

Assume ACω. Give PU(2) the quotient metric from Projective braid gate and operator metric. The map q:SU(2)⟶PU(2),q(A)=[A], is a two-sheeted covering with kernel {I,−I}. It induces a topological group isomorphism SU(2)/{±I}≅PU(2)≅SO(3).

Facts & Assumptions

Given: The projective unitary group PU(2) with its quotient metric, the matrix group SU(2), and ACω.

[F1]

The projective distance is a metric and dP([A],[B])=min⁡∣z∣=1∥A−zB∥op. Projective braid gate and operator metric

[F4]

Every unit complex number has the form eiθ for some real θ. t↦(cos⁡t,sin⁡t) is a bijection from [0,2π) onto the real unit circle

[F5]

Quaternionic conjugation gives a surjective two-sheeted covering ρ:SU(2)→SO(3) with kernel {I,−I}. SU(2) to SO(3) as a covering homomorphism

[A1]

Assume ACω, the exact choice principle used by [F5]. The Axiom of Countable Choice (ACω)

Proof

1.1givenF4algebra

The determinant of a unitary A∈U(2) has modulus one, since 1=det⁡(A∗A)=det⁡A‾det⁡A. Write det⁡A=eiθ by [F4] and put λ=e−iθ/2. Then ∣λ∣=1 and det⁡(λA)=λ2det⁡A=1, so λA∈SU(2) and q(λA)=q(A). Thus q is onto.

2.1givenstep 1.1algebra

If A∈SU(2) and q(A)=[I], then A=λI for some ∣λ∣=1. The determinant condition gives λ2=1, hence λ=±1. Conversely I and −I have the same projective class. Therefore ker⁡q={±I}, and two matrices have the same q-image exactly when they differ by this kernel.

2.2F1F2F3step 1.1algebra

The map q is continuous: by [F1], dP(q(A),q(B))≤∥A−B∥op. Identify M2(C) with R8. The equations A∗A=I and det⁡A=1 define a closed subset, and each matrix entry is bounded in modulus by 1 because each column has norm 1. Thus SU(2) is compact by [F2]. The metric space PU(2) is Hausdorff by [F1]. If F⊆SU(2) is closed, then it is compact and q(F) is compact, hence closed by [F3]. It is a quotient map: if q−1(W) is open, then q−1(PU(2)∖W) is closed; surjectivity and closedness of q make its image PU(2)∖W closed, so W is open.

3.1A1F3F5step 2.1step 2.2algebra∎

By [F5] and step 2.1, q and ρ have exactly the same fibers. There is therefore a unique bijective group homomorphism ρˉ:PU(2)→SO(3) with ρˉ(q(A))=ρ(A). It is continuous because q is a quotient map and ρ=ρˉ∘q is continuous. The space PU(2)=q(SU(2)) is compact, while SO(3) is Hausdorff as a subspace of the real 3×3 matrix space. A continuous bijection from a compact space to a Hausdorff space is a homeomorphism: images of closed sets are compact and therefore closed by [F3]. Hence ρˉ is a topological group isomorphism. Since q is a quotient map and its fibers are exactly the cosets of {±I} by step 2.1, the induced map SU(2)/{±I}→PU(2) is also a homeomorphism. The covering sheets for q are carried from those of ρ by this homeomorphism, so q is a two-sheeted covering.

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