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Dense projective SU(2) image has dense determinant-one lifts

Statement

Assume ACω. Let q:SU(2)→PU(2) be the quotient by {±I}, and let Γ≤PU(2) be dense. Then the full inverse image q−1(Γ) is dense in SU(2). Thus projective density gives determinant-one lifts arbitrarily close to any SU(2) target, while the choice of a lift can differ by the central sign.

Facts & Assumptions

Given: The two-sheeted covering homomorphism q:SU(2)→PU(2) and a dense subgroup Γ≤PU(2).

[F1]

q:SU(2)→PU(2) is a two-sheeted covering with kernel {±I}. The projective one-qubit group is SO(3)

[F2]

By the given density hypothesis, Γ meets every nonempty open subset of PU(2).

[A1]

ACω is the axiom assumed by the covering supplier. The Axiom of Countable Choice (ACω)

Proof

1.1givenF1choose

Let O be any nonempty open subset of SU(2) and choose u∈O. By [F1], there is an evenly covered neighborhood N0 of q(u) and a sheet S0 containing u such that q∣S0:S0→N0 is a homeomorphism. Set S=S0∩O and N=q(S). Since S is open in S0, N is open in N0; the restriction q∣S:S→N remains a homeomorphism.

2.1A1F1F2step 1.1choose∎

The open set N meets Γ by [F2]; choose g∈N∩Γ. Its unique lift v∈S lies in O and satisfies q(v)=g, hence v∈q−1(Γ). Thus every nonempty open O meets q−1(Γ), which is exactly density in SU(2). The only stated axiom is [A1].

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