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The empirical spectral distribution of a sample covariance matrix is a probability measure

Statement

For positive integers n,p and a real matrix X∈Rn×p, set S(X)=XTX/n and μS(X)=p−1∑j=1pδλj(S(X)), where the eigenvalues are counted with multiplicity. Then μS(X) is a Borel probability measure on R, supported on [0,∞).

Statement references

Bai and Silverstein, Chapter 3, §3.1, printed pp. 39–40 (complete book PDF).

Facts & Assumptions

Given: Positive integers n,p and X∈Rn×p.

[F1]

Sample covariance matrices and their empirical spectral distributions defines S(X)=XTX/n and μS(X)=p−1∑j=1pδλj(S(X)).

[F3]

For every finite list of points of a measurable space, the equally weighted sum of their Dirac measures is a probability measure (A finite empirical measure is a probability law).

Proof

1.1givenF1F2algebra

The matrix S(X) is symmetric because (XTX)T=XTX. For every v∈Rp, vTS(X)v=1n∥Xv∥22≥0. By [F2], its eigenvalues are real; if S(X)v=λv with v≠0, the displayed quadratic-form identity gives λ∥v∥22≥0, hence λ≥0.

2.1F1F3step 1.1∎

Apply [F3] to the finite list λ1(S(X)),…,λp(S(X)) in the Borel space R. The resulting empirical measure is exactly [F1] and is a Borel probability measure. Step 1.1 shows it assigns no mass outside [0,∞).

Depends on

Used by

Cited to discharge well-definedness by Sample covariance matrices and their empirical spectral distributions.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources